We have that
[3/2,3/8,3/32,3/128,3/512]
the sum of the geometric sequence is [3/2+3/8+3/32+3/128+3/512]
=(1/512)*[256*3+64*3+16*3+4*3]
=(3/512)*[256+64+16+4]
=(3/512)*[340]
=(1020/512)
=255/128---------> 1.9922
the answer is
1.9922
another way to calculate it
<span>is through the following formula
</span>∑=ao*[(1-r<span>^n)/(1-r)]
</span>
where
ao---------> is the first term
r----------> is the common ratio<span> between terms
n----------> </span><span>is the number of terms
ao=1.5
r=1/4-----> 0.25
n=5
so
</span>∑=1.5*[(1-0.25^5)/(1-0.25)]-------------> 1.99
Answer: -35.375 or -283/8
Step-by-step explanation:
Begin with the parenthese: (-1.5+9.5)=8 and (7+11)
Then you have 5/8+0.4(18)/-0.2.
Multiply 0.4 times that 18 and you get 7.2.
Then you have 5/8+7.2/-0.2
Simplify 7.2/-0.2 which equals -36
Then you have 5/8+-36
5/8+-36=-35.375 or in fraction form -283/8
Answer:
Step-by-step explanation: