Javia ran 8 laps around a track to run a total of 1 mile on Monday. How many laps will she need to run on Tuesday to run 3/8 of
1 answer:
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<em>Question 1: </em>
For this case we have the following pattern of numbers:
24.3, 24, 23.7, 23.4
It can be seen that subtracting 0.3 from the first number of the pattern gives
Equally if we subtract 0.3 successively we obtain:
Thus, 0.3 must be subtracted from each term and the following numbers of the pattern shall be 23.1 and 22.8
Answer:
subtract 0.3 from each term
The next two numbers of the pattern are 23.1 and 22.8
<em>Question 2: </em>
For this case we have the following operation:
We note that the sum is greater than 1
The sum of two hundredth decimals does not necessarily have to be greater than 1.
Therefore, the correct option is: the sum is greater than 1 because the sum shades more than one hundredths grid.
Answer:
Option C
<em>Question 3: </em>
For this case we have to:
Being a, b, c decimal numbers, one of them was 0.34. Suppose
Thus:
We choose values for b and c, in order to obtain the number 2 as a result of the sum. We can choose infinite values so that equality is fulfilled
If and
we have:
Thus, Holland can add to the sum and
Answer:
<em>Question 4: </em>
For this case we have the following subtraction:
This operation is wrong, subtracting results in 1.04
Let's explain a model for Maysa:
We have the following expression
Rewriting each number in expanded form we have:
Using the distributive property we have:
Using the associative property we have:
Performing each operation:
Anwer:
The subtraction of Maysa is wrong, the correct answer is:
Answer:
The 95% confidence interval for the mean time for all players, in minutes, is: (7.95, 11.01).
Step-by-step explanation:
We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.
The first step to solve this problem is finding how many degrees of freedom,which is the sample size subtracted by 1. So
df = 10 - 1 = 9
95% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 9 degrees of freedom(y-axis) and a confidence level of . So we have T = 2.2622.
The margin of error is:
In which s is the standard deviation of the sample and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 9.48 - 1.53 = 7.95 minutes.
The upper end of the interval is the sample mean added to M. So it is 9.48 + 1.53 = 11.01 minutes.
The 95% confidence interval for the mean time for all players, in minutes, is: (7.95, 11.01).