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3 years ago

How Ro U Sovle This Problem Bc I Don't Know How?

Mathematics

1 answer:

marissa [1.9K]3 years ago

3 0

You would have to transform the fractions to decimals by dividing. For the first one, if you divide 4 by 5 you get .8. To transform a decimal to percent you move the decimal place 2 times to the right or multiply by 100 (They both would give you the same thing)

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DEF is a dilation image of ABC. What is the scale factor?

horsena [70]

Answer:

Option (2)

Step-by-step explanation:

ΔDEF is a dilation image of ΔABC.

Rule for the dilation,

Scale factor = $\frac{\text{Length of one side of the image triangle}}{\text{Length of one side of the original triangle}}$

= $\frac{DE}{AB}$

= $\frac{4}{8}$

= $\frac{1}{2}$

Therefore, scale factor by which ΔABC is dilated is $\frac{1}{2}$ .

Option (2) will be the correct option.

7 0

2 years ago

What is the value of the exponital expression below 36 1/2

Vedmedyk [2.9K]

The answer is 6.

36^ 1/2 = the square root of 36 = 6

8 0

3 years ago

Find the distance between two points (2, -3) and (2,4).

Damm [24]

Answer:

The distance between the two points is 7 units

Step-by-step explanation:

we know that

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

we have

(2, -3) and (2,4)

substitute the values in the formula

$d=\sqrt{(4+3)^{2}+(2-2)^{2}}$

$d=\sqrt{(7)^{2}+(0)^{2}}$

$d=7\ units$

6 0

3 years ago

A 555-mile, 5-hour plane trip was flown at two speeds. For the first part of the trip, the average speed was 105 mph. Then the t

Pepsi [2]

Answer:

Hence Distance traveled at speed 115 mph is 345 miles and Distance traveled at speed 105 mph is 210 miles.

Step-by-step explanation:

Given:

Total Distance = 555 mile

Total time = 5 hour

Let time taken to travel at 115 mph be t

So Time taken to travel at 105 mph will be equal to difference between Total time and time taken to travel at 115 mph.

Time taken to travel at 105 mph = $5-t$

Distance traveled in speed 105 mph will be equal to speed multiplied by time taken to travel at 105 mph.

Framing in equation form we get;

Distance traveled in 115 mph = $115t$

Also;

Distance traveled in speed 105 mph will be equal to speed multiplied by time taken to travel at 105 mph.

Framing in equation form we get;

Distance traveled in 105 mph = $105(t-5) = 105t - 525$

Now Total Distance traveled is equal sum of Distance traveled in 115 mph and Distance traveled in speed 105 mph

$115t-(105t-525)=555\\\\115t-105t+525=555\\\\10t+525=555\\\\10t=555-525\\\\10t=30\\\\t=\frac{30}{10}=3$

Time taken to travel at 115 mph = 3 hrs.

Time taken to travel at 105 mph = $5-t=5-3=2\ hrs$

Now Distance traveled in 115 mph = $115t = 115 \times 3 = 345\ miles$

Distance traveled in 105 mph = $105(5-t) = 105(5-3)= 105\times 2 = 210\ miles$

Hence Distance traveled at speed 115 mph is 345 miles and Distance traveled at speed 105 mph is 210 miles.

6 0

3 years ago

Jack and Walter work in a store's gift-wrapping department. Jack can wrap 28 boxes in 2 hours, while Walter takes 3 hours to wra

kodGreya [7K]

Answer:

Step-by-step explanation:

Jack's rate = 28/2 = 14 boxes/hour

Walter's rate = 36/3 = 12 boxes/hour

Combined rate = 14 + 12

= 26 boxes/hour

26 = 65/t

26t = 65

3 0

3 years ago