Answer:
Width is 10 Length is 20
Step-by-step explanation:
Perimeter = 60
Length = W + 10
P = 2L + 2W Write the equation for perimeter
60 = 2(W + 10) + 2W Substitute your variables
60 = 4W + 20
- 20 - 20 Subtract 20 from both sides
40 = 4W Divide both sides by 4
10 = W
Answer:
no solution
Step-by-step explanation:
Given
(21 - 3a) = 6 - a ( multiply through by 3 to clear the fraction )
21 - 3a = 18 - 3a ( subtract 21 from both sides )
- 3a = - 3 - 3a ( add 3a to both sides )
0 = - 3 ← not possible
This indicates the equation has no solution
Answer:
<h2>2/5</h2>
Step-by-step explanation:
The question is not correctly outlined, here is the correct question
<em>"Suppose that a certain college class contains 35 students. of these, 17 are juniors, 20 are mathematics majors, and 12 are neither. a student is selected at random from the class. (a) what is the probability that the student is both a junior and a mathematics majors?"</em>
Given data
Total students in class= 35 students
Suppose M is the set of juniors and N is the set of mathematics majors. There are 35 students in all, but 12 of them don't belong to either set, so
|M ∪ N|= 35-12= 23
|M∩N|= |M|+N- |MUN|= 17+20-23
=37-23=14
So the probability that a random student is both a junior and social science major is
=P(M∩N)= 14/35
=2/5
Answer:
inside
√((5-(-5))^2+((-24)-(-8))^2)=√(10^2+16^2)=√356＜25
