tan2x*cotx - 3 = 0
We know that: tan2x = sin2x/cos2x and cotx = cosx/sinx
==> sin2x/cos2x *cosx/sinx = 3
Now we know that sin2x = 2sinx*cosx
==> 2sinxcosx/cos2x * cosx/sinx = 3
Reduce sinx:
==> 2cos^2 x/ cos2x = 3
Now we know that cos2x = 2cos^2 x-1
==> 2cos^2 x/(2cos^2 x -1) = 3
==> 2cos^2 x = 3(2cos^2 x -1)
==> 2cos^2 x = 6cos^2 x - 3
==> -4cos^2 x= -3
==> 4cos^2 x = 3
==> cos^2 x = 3/4
==> cosx = +-sqrt3/ 2
<span>==> x = pi/6, 5pi/6, 7pi/6, and 11pi/6</span>
Answer:
2√(17) or about 8.2462 units.
Step-by-step explanation:
We want to determine the distance between the two points (-10, -7) and (-8, 1).
We can use the distance formula. Recall that:

Substitute and evaluate:

Hence, the distance between (-10, -7) and (-8, 1) is 2√(17) units or about 8.2462 units.
Answer:
1/8 or
1 1/2
Step-by-step explanation:
necesitas contar la xx
Answer:
-3
Hope this helps :)
Have a great day !
5INGH
Step-by-step explanation:
