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Musya8 [376]
2 years ago
10

Equations in Iwo V Solve the system by the addition method. 3x+8y=6 3x-8y=6 Select the correct choice below and, if necessary, f

ill in the answer box to complete your choice. OA. There is exactly one solution. The solution set is ‹› (Simplify your answer. Type an ordered pair.) B. There are infinitely many solutions. The solution set is {(x,y)|3x + 8y = 6) or ((x,y)|3x - 8y = OC. The solution set is Ø.​
Mathematics
2 answers:
yanalaym [24]2 years ago
6 0

Answer:

hello there buddy I’m here too help you with your homework

Your answer is

A.there is exactly one solution. the solution set is {(2, 0)}.

Hope it’s helps you

Have a nice day

Good luck with your homework

Step-by-step explanation:

~Sheesh

sweet [91]2 years ago
4 0

Answer:

A. there is exactly one solution. the solution set is {(2, 0)}.

Step-by-step explanation:

3x + 8y = 6

3x - 8y = 6

when we add these 2 equations, we get

6x + 0 = 12

6x = 12

x = 2

now we use one of the original equations to get y :

3×2 + 8y = 6

6 + 8y = 6

8y = 0

y = 0

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I don’t understand this!!
Rufina [12.5K]

Answer:

9, 11, 13

Step-by-step explanation:

We can rephrase an odd number into an algebraic equation of (2n+1)

Therefore, 3 consecutive odd numbers would be written as:

(2n+1), (2n+3), (2n+5)

We can then rewrite the question as:

3 x (2n+1) = 2 x (2n+5) + 1

Work out the equation to find n:

6n + 3 = 4n + 10 + 1

(minus 4n from both sides)

2n + 3 = 11

(minus 3 from both sides)

2n = 8

(divide both sides by 2 to get)

n = 4

To find the original 3 consecutive numbers, we just input (4) into (2n+1), (2n+3), (2n+5) to get:

(8+1), (8+3), (8+5)

= 9, 11 and 13

6 0
3 years ago
Badel has 120 cm³ of water he wants to pour into a rectangular base that is 4 cm high 40 mm wide and 5 cm long will all the wate
Elenna [48]
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4 years ago
CAN YOU HELP ME,TYvery much
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Answer:

C

Step-by-step explanation:

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Answer:

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Some body can help me with a geometric mean maze
Mars2501 [29]

Answer:

See explanation

Step-by-step explanation:

Theorem 1: The length of the altitude to the hypotenuse of a right triangle is the geometric mean of the lengths of the segments of the hypotenuse.

Theorem 2: The length of each leg of a right triangle is the geometric mean of the length of the hypotenuse and the length of the segment of the hypotenuse adjacent to that leg.

1. Start point: By the 1st theorem,

x^2=25\cdot (49-25)=25\cdot 24=5^2\cdot 2^2\cdot 6\Rightarrow x=5\cdot 2\cdot \sqrt{6}=10\sqrt{6}.

2. South-East point from the Start: By the 2nd theorem,

x^2=40\cdot (40+5)=4\cdot 5\cdot 2\cdot 9\cdot 5\Rightarrow x=2\cdot 5\cdot 3\cdot \sqrt{2}=30\sqrt{2}.

3. West point from the previous: By the 2nd theorem,

x^2=(32-20)\cdot 32=4\cdot 3\cdot 16\cdot 2\Rightarrow x=2\cdot 4\cdot \sqrt{6}=8\sqrt{6}.

4. West point from the previous: By the 1st theorem,

9^2=x\cdot 15\Rightarrow x=\dfrac{81}{15}=\dfrac{27}{5}=5.4.

5. West point from the previous: By the 2nd theorem,

10^2=8\cdot (8+x)\Rightarrow 8+x=12.5,\ x=4.5.

6. North point from the previous: By the 1st theorem,

x^2=48\cdot 6=6\cdot 4\cdot 2\cdot 6\Rightarrow x=6\cdot 2\cdot \sqrt{2}=12\sqrt{2}.

7. East point from the previous: By the 2nd theorem,

x^2=22.5\cdot 30=225\cdot 3\Rightarrow x=15\sqrt{3}.

8. North point from the previous: By the 1st theorem,

x^2=7.5\cdot 36=270\Rightarrow x=3\sqrt{30}.

8. West point from the previous: By the 2nd theorem,

x^2=12.5\cdot (12.5+13.5)=12.5\cdot 26=25\cdot 13\Rightarrow x=5\sqrt{13}.

9. North point from the previous: By the 1st theorem,

12^2=x\cdot 30\Rightarrow x=\dfrac{144}{30}=4.8.

101. East point from the previous: By the 1st theorem,

6^2=1.6\cdot (x-1.6)\Rightarrow x-1.6=22.5,\ x=24.1.

11. East point from the previous: By the 2nd theorem,

20^2=32\cdot (32-x)\Rightarrow 32-x=12.5,\ x=19.5.

12. South-east point from the previous: By the 2nd theorem,

18^2=x\cdot 21.6\Rightarrow x=15.

13. North point=The end.

6 0
3 years ago
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