Question

Find an equation of the line perpendicular to 7x+2y+3y+1=0 through the point (-2, 1)

Answer 1

Answer:

The equation of the line would be y = 5/7x + 17/7

Step-by-step explanation:

In order to solve this, start by finding the slope of the original line. You can do this by solving for y.

7x + 2y + 3y + 1 = 0

7x + 5y + 1 = 0

5y = -7x - 1

y = -7/5x - 1/5

Now that we have a slope of -7/5, we know that the perpendicular slope is 5/7 (since perpendicular lines have opposite and reciprocal slopes). We can use this and the new point in point-slope form to find the equation.

y - y1 = m(x - x1)

y - 1 = 5/7(x + 2)

y - 1 = 5/7x + 10/7

y = 5/7x + 17/7