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LUCKY_DIMON [66]
3 years ago
5

Catering question What is the hottest food in the world

Computers and Technology
1 answer:
Elza [17]3 years ago
7 0
The hottest food in the world is a Ghost Pepper. It is 400 times hotter than Tabasco sauce. It was 1 million SHU's! Hope this helps! ^0^

The correct answer is: Ghost Peppers
You might be interested in
In one sentences describe how to change your home page
3241004551 [841]

Click Tools, Internet options. ...The Internet Options window will open. ...Click Apply, OK to close the window.Click the wrench icon in the top-right corner of the browser.Select Options.In the 'On startup' section, select Open the home page.options window will open. Go to the Startup section and select When Firefox starts: Show my home page.. In the Home Page field, type in the website address you want to use as your home page.Click OK.


4 0
2 years ago
This program will store roster and rating information for a soccer team. Coaches rate players during tryouts to ensure a balance
Simora [160]

Answer:

// Scanner class is imported to allow program receive user input

import java.util.Scanner;

// class is defined

public class PlayerRoster {

   // main method that begin program execution

  public static void main(String[] args) {

   // Scanner object scan is defined

     Scanner scan = new Scanner(System.in);

   // multi-dimensional array to hold the jersey number and rating

     int[][] players = new int[5][2];

   // boolean flag to keep program alive

     boolean keepAlive = true;

   // the user input is declared as input of type char

     char input;

     

   // for loop that receive 5 player jersey number and ratings

   // it assigns the received input to the already initialized array

     for (int i = 0; i < 5; i++) {

        System.out.println("Enter player " + (i+1) + "'s jersey number: ");

        players[i][0] = scan.nextInt();

        System.out.println("Enter player " + (i+1) + "'s rating: ");

        players[i][1] = scan.nextInt();

        System.out.println();

     }

   // a blank line is printed

     System.out.println();

   // a method is called to display players array

     outputRoster(players, 0);

     

   // while the flag is true

   // display the Menu by calling the outputMenu method

     while (keepAlive) {

        outputMenu();

       // user input is assigned to input

        input = scan.next().charAt(0);

       //  if user input is 'q' then program will quit

        if (input == 'q') {

           keepAlive = false;

           break;

        }

       //  else if input is o, then outputRoaster is called to display players

        else if (input == 'o') {

           outputRoster(players, 0);

        }

       //  else if input is 'u', then user is allowed to edit a player rating

        else if (input == 'u') {

           System.out.println("Enter a jersey number: ");

           int jerseyNum = scan.nextInt();

           System.out.println("Enter a new rating for the player: ");

           int newRating = scan.nextInt();

           for (int l = 0; l < 5; l++) {

              if (players[l][0] == jerseyNum) {

                 players[l][1] = newRating;

              }

           }

        }

       //  else if input is 'a', user is allowed to add a new rating

        else if (input == 'a') {

           System.out.println("Enter a rating: ");

           int rating = scan.nextInt();

           outputRoster(players, rating);

        }

        // else if input is 'r', user is allowed to replace a player

        else if (input == 'r') {

           System.out.println("Enter a jersey number: ");

           int jerseyNum = scan.nextInt();

           boolean exists = true;

           for (int l = 0; l < 5; l++) {

              if (players[l][0] == jerseyNum) {

                 System.out.println("Enter a new jersey number: ");

                 players[l][0] = scan.nextInt();

                 System.out.println("Enter a rating for the new player: ");

                 players[l][1] = scan.nextInt();

              }

           }

           

        }

     }

     

     return;

  }

 

// this method take two parameters, players and min

// it then returns player with ratings greater than min

  public static void outputRoster(int[][] players, int min) {

     System.out.println(((min>0) ? ("ABOVE " + min) : ("ROSTER")));

     int item = 1;

     for (int[] player : players) {

        if (player[1] > min) {

           System.out.println("Player " + item + " -- Jersey number: " + player[0] + ", Rating: " + player[1]);

        }

        item++;

     }

     System.out.println();

  }

 

// outputMenu method to display the program menu

  public static void outputMenu() {

     System.out.println("MENU");

     System.out.println("u - Update player rating");

     System.out.println("a - Output players above a rating");

     System.out.println("r - Replace player");

     System.out.println("o - Output roster");

     System.out.println("q - Quit\n");

     System.out.println("Choose an option: ");  

  }

}

Explanation:

The program is written in Java and it is well commented.                                          

5 0
3 years ago
A media file refers to what kind of file? A. Clip art
prohojiy [21]

Waveform Audio (.wav) is a common file format. Created by Microsoft and IBM, WAV was one of the first audio file types developed for the PC. WAV files are defined as lossless, meaning that files are large and complete; nothing has been lost.

your answer will be

<h2><em><u>C; image</u></em></h2>
5 0
3 years ago
Read 2 more answers
Which of the following data types can hold a fractional (decimal) number?
zvonat [6]
A float data type can hold a decimal number.
6 0
2 years ago
For a list to be binary search-able, we need the following thing to be true, because... a. The list must be sorted, because chec
rusak2 [61]

Answer:

The answer is option A.

Explanation:

Negative numbers can be found by binary search, this makes option B incorrect.

Unsorted and randomized lists are also not things that support a binary search, options C and D are incorrect.

Binary search uses a technique where the middle element of the list is located and used to determine whether the search should be done within the lower indexed part of the list or the higher. So for a list to be binary search-able, it should be sorted and not randomized.

The answer is A.

I hope this helps.

7 0
3 years ago
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