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dlinn [17]
4 years ago
12

Trig Problem number 34. 10cosx+8sqrt2=8cos+7sqrt2

Mathematics
1 answer:
AlladinOne [14]4 years ago
4 0

Answer:

10 cos x +8sqrt2 = 8cos x +7 sqrt2   collect like times together to have

10cosx-8cosx = 8√2 - 7√2 then solve to have

2cosx = √2    divide by two in both sides

cosx=√2/2     but 2= √2 *√2

so cosx= √2/(√2 * √2)   so cos x =1/√2  but we know that cos inverse of 1/√2= 45   thus cos 45 = 1/√2 thus x = 45

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IND 11. Kim is arranging magazines on shelves. She has 18 sports magazines and 24 news magazines. Each shelf will have the same
Lisa [10]

Find the multiples of each number:

18: 1 , 2 , 3 , 6 , 9 , 18

24: 1, 2, 3, 4, 6 , 8, 12, 24

Now find the matching numbers:

1 , 2, 3 , 6

7 0
3 years ago
Plz help ill give brainliest
horrorfan [7]

Answer:

Step-by-step explanation:

Cone

Givens

r = 1.5 inches

h = 4 inches

Formula

V = 1/3 pi r^2 h

V = 1/3 3.14 * 1.5^2 * 4

V = 1/3* 3.14 * 2.25 * 4

V = 9.42

Semi sphere

Givens

r = 1.5

Formula

V = 2/3 * pi * r^3

Solution

V = 2/3 * 3.14 * 1.^3

V = 7.065

Total

V = 9.42 + 7.065

V = 16.485

Rounded to the nearest 1/100

V = 16.49

Answer

First left column = 0

Next left column= 1

Tens column          6

Then the decimal  .

Next column          4               (Tens column)

Hundredths           9

8 0
3 years ago
Please help!❤️<br><br> 9/4y-2=25<br> Please solve and show work!!
STatiana [176]
9/4y-2=25
9/4y-2+2=27+2
9/4y=27
9/4y*4y=27*4y
9=4y*27,
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Answer:y=1/12
8 0
3 years ago
Read 2 more answers
The solution to 2x2 – 11 = 87 is
Ilia_Sergeevich [38]
2x^2 - 11 = 87
2x^2 = 87 + 11 = 98
x^2 = 98/2 = 49
x = sqrt (49) =  + or - 7
7 0
3 years ago
Read 2 more answers
Explain how to use the vertex and the value of “A” to determine the range of an absolute value function. PLEASE HELP!!
Thepotemich [5.8K]

Answer:

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y = f(x) = IxI

remember how this work:

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Notice that I0I = 0.

And the range of this function is all the possible values of y.

For example for the parent function IxI, the range will be all the positive reals and the zero.

First, if A is the value of the vertex of the absolute function, then we know that A is the maximum or the minimum value of the function.

Now, if the arms of the graph open up, then we know that A is the minimum of the function, and the range will be:

y ≥ A

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if the arms of the graph open downwards, then A is the maximum of the function, and we have that the range is:

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5 0
4 years ago
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