The distance between the two streets along Kendall is 347.9 feet.
Solution:
The image of the problem is attached below.
Distance between Wilmington to Ash Grove along Kendall = 820 feet
Distance between Wilmington to Ash Grove along Magnolia = 660 feet
Distance between Beech and Ash Grove along Magnolia = 280 feet
Distance between Wilmington to Beech along Magnolia
= 660 feet – 280 feet
= 380 feet
Let us x be the distance between Wilmington to Beech along Kendall and
820 – x be the distance between Beech and Ash Grove along Kendall.
The given streets are parallel.
By proportionality theorem, parallel lines cut by a transversal are in proportion.
Do cross multiplication.
Distance between Beech and Ash Grove along Kendall
= 820 – x
= 820 – 472.1
= 347.9
Hence the distance between the two streets along Kendall is 347.9 feet.
Each pair of tangents to a point makes two congruent segments to the circle. So if we label all the little segments, say clockwise starting at the top, we get
27, 22, 22, 98, 98, 22, 22, 27
The sum is 338
Answer: 338 in
8CM is equivalent to 80 millimeters
Answer:
$996
Step-by-step explanation:
The rectangular plot has an area that is the product of its length and width. We are given the width as 12 feet, and the area as 240 ft², so we can find the length from ...
... A = L×W
... 240 ft² = L×(12 ft)
... 240 ft²/(12 ft) = L = 20 ft
Opposite sides of the rectangle are the same length, so the cost of fence for a side of a given length will be the sum of the costs of the opposites sides.
The 12 ft side has one segment that is $18 per foot, and one that is $15 per foot. For the 20 ft sides, both are $15 per foot. Then the total cost can be figured from ...
... (12 ft)·($18/ft + $15/ft) + (20 ft)·($15/ft +$15/ft) = 12·$33 +20·$30 = $996
You can use photomath it is a great app to find ONLY equations!
