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kicyunya [14]
3 years ago
7

MAPS On a map, Wilmington Street, Beech Drive, and Ash Grove Lane appear to all be parallel. The on

Mathematics
1 answer:
joja [24]3 years ago
8 0

The distance between the two streets along Kendall is 347.9 feet.

Solution:

The image of the problem is attached below.

Distance between Wilmington to Ash Grove along Kendall = 820 feet

Distance between Wilmington to Ash Grove along Magnolia = 660 feet

Distance between Beech and  Ash Grove along Magnolia = 280 feet

Distance between Wilmington to Beech along Magnolia

                                       = 660 feet – 280 feet

                                       = 380 feet

Let us x be the distance between Wilmington to Beech along Kendall and

820 – x be the distance between Beech and  Ash Grove along Kendall.

The given streets are parallel.

By proportionality theorem, parallel lines cut by a transversal are in proportion.

$\Rightarrow\frac{380}{280} =\frac{x}{820-x}

Do cross multiplication.

$\Rightarrow{380}({820-x}) =280x

$\Rightarrow 311600-380x =280x

$\Rightarrow 311600 =280x+380x

$\Rightarrow 311600 =660x

$\Rightarrow x=472.1

Distance between Beech and  Ash Grove along Kendall          

                                    = 820 – x  

                                    = 820 – 472.1

                                    = 347.9

Hence the distance between the two streets along Kendall is 347.9 feet.

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a rectangular wall with a length of 10x and width of 20 x has a rectangular doorway with a length of 5x and a width of 2x. What
Shtirlitz [24]

Answer:

∴ The the surface area of the wall is 190x^{2} \ square\ unit.

Step-by-step explanation:

Given that,

                 The length of rectangular wall is 10x.

                 The width of rectangular wall is 20x.

                 The length of doorway is 5x.

                 The width of doorway is 2x.

and, we have to find the surface area of rectangular wall.

Now,

The length of rectangular wall is 10x.

The width of rectangular wall is 20x.

∴ Total surface area of a rectangular wall = Length\ of\ wall\times Width\ of\ wall

                                                                     = 10x\times 20x

                                                                     = 200x^{2} \ square\ unit

Total surface area of a rectangular wall is 200x^{2} \ square\ unit.

Again, The length of doorway is 5x.

           The width of doorway is 2x.

∴Total surface area of doorway =Lenght\ of\ doorway\times Width\ of\ doorway

                                                     =5x\times 2x

                                                     =10x^{2} \ square\ unit

Total surface area of doorway is 10x^{2} \ square\ unit.

∴The remaining surface area of a rectangular wall is = 200x^{2} -10x^{2}                                                                                                        

                                                                                           =190x^{2} \ square\ unit

∴ The the surface area of the wall is 190x^{2} \ square\ unit.

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e=16

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