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egoroff_w [7]
3 years ago
9

How to solve for a side in right triangles

Mathematics
2 answers:
Volgvan3 years ago
8 0
Pythagorean theorem
Serjik [45]3 years ago
6 0

Answer:

use the Pythagorean theorem a^2+b^2=C^2 where c is the length of the hypotenuse, or the length of the side opposite of the right angle. a and b are the length of the 2 smallest sides.

Step-by-step explanation:

hope this helps

Please mark me brainliest. It would help(✿◠‿◠)

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The perimeter of a given rectangle is equal to the circumference of a given circle. The circle has radius 30 inches; the width o
Arte-miy333 [17]
The answer to this question will be E
7 0
3 years ago
Read 2 more answers
75c- 300 - 35 c =25c + 15c + 200
GarryVolchara [31]

Answer:

False

Step-by-step explanation:

40c - 300 = 40c + 200

-300 = 200

false

4 0
3 years ago
3. Try It #3 Write the point-slope form of an equation of a line with a slope of -2 that passes through the point (-2,2). Then r
vova2212 [387]

Answer:

Point-slope form of equation given as $y-2=-2(x+2)$.

Slope-intercept form of equation is given as $y=-2 x-2$.

Step-by-step explanation:

In the question, it is given that the slope of a line is -2 and it passes from (-2,2).

It is asked to write the point-slope form of the equation and rewrite it as slope-intercept form.

To do so, first find the values which are given in the question and put it in the formula of point-slope form. Simplify the equation to rewrite as slope-intercept form.

Step 1 of 2

Passing point of the line is (-2,2).

Hence, $x_{1}=-2$ and

$$y_{1}=2 \text {. }$$

Also, the slope of the line is -2.

Hence, m=-2

Substitute the above values in point-slope form of equation given by $y-y_{1}=m\left(x-x_{1}\right)$

$$\begin{aligned}&y-y_{1}=m\left(x-x_{1}\right) \\&y-2=-2(x-(-2) \\&y-2=-2(x+2)\end{aligned}$$

Hence, point-slope form of equation given as y-2=-2(x+2).

Step 2 of 2

Solve y-2=-2(x+2) to write it as slope-intercept form given by y=mx+c.

$$\begin{aligned}&y-2=-2(x+2) \\&y-2=-2 x-4 \\&y=-2 x-4+2 \\&y=-2 x-2\end{aligned}$$

Hence, slope-intercept form of equation is given as y=-2x-2.

7 0
2 years ago
A quilted block users eight parallelogram shaped pieces of clothe each with a base of 3/3/4 inches. How much fabric is needed to
borishaifa [10]

Answer:

The answer to the question is

37.5 ft² of fabric is needed to make the parallelogram pieces for 24 blocks.

Step-by-step explanation:

To answer the question, we note that  a parallelogram is a four sided polygon having two opposite parallel sides.

Therefore in this question, we select our parallelogram to be a rectangle

Number of pieces of parallelogram in a quilted block = 8

Number of parallelogram in each quadrant of the quilted block = 2

Therefore the height of the rectangle = 2 × the base = 2×3\frac{3}{4} = 7.5 inches

Therefore the area of each parallelogram = base × height

= \frac{15}{4}*\frac{15}{2} = \frac{225}{8} in²

since each quilted block uses 8 parallelogram, then the amount of fabric for each quilted block is

\frac{225}{8} *8 = 225 in^2

Hence 24 blocks wil require 24×225 in² = 5400 in²

However, since 144 in² = 1 ft² we have

5400 in² = 5400 in²× 1/144  ft²/in² = 37.5 ft².

7 0
3 years ago
If BD is the midsegment and BD is parallel to to AE, then value of AE is
Flura [38]
112 is correct, 56 times 2.
3 0
3 years ago
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