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umka2103 [35]
3 years ago
12

Find the measure of the missing angles.

Mathematics
1 answer:
oksano4ka [1.4K]3 years ago
4 0

We know that vertically opposite angles are equal.

So, k = 131° [Vertically opposite angles]

and g = 43° [Vertically opposite angles]

We know that linear pair of angles are supplementary (180°).

So, h + 43° = 180° [Linear pair of angles]

=> h = 180° - 43°

=> h = 137°

and m + 131° = 180° [Linear pair of angles]

=> m = 180° - 131°

=> m = 49°

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4x+4+8=24
4x+12=24
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4x =12
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2 years ago
What’s the slope of a parallel line given the equation 3x+4y=3? <br><br> Please explain the process.
Otrada [13]

Answer:

-3/4

Step-by-step explanation:

Move the 3x over to the side with the 3 so it will become a -3x now you have 4y=-3x+3 now you have to remove the 4 from the y so now you have y=-3/4x+3/4 so you slope will be -3/4

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2 years ago
All the fourth-graders in a certain elementary school took a standardized test. A total of 85% of the students were found to be
Aneli [31]

Answer:

There is a 2% probability that the student is proficient in neither reading nor mathematics.

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that a student is proficient in reading

B is the probability that a student is proficient in mathematics.

C is the probability that a student is proficient in neither reading nor mathematics.

We have that:

A = a + (A \cap B)

In which a is the probability that a student is proficient in reading but not mathematics and A \cap B is the probability that a student is proficient in both reading and mathematics.

By the same logic, we have that:

B = b + (A \cap B)

Either a student in proficient in at least one of reading or mathematics, or a student is proficient in neither of those. The sum of the probabilities of these events is decimal 1. So

(A \cup B) + C = 1

In which

(A \cup B) = a + b + (A \cap B)

65% were found to be proficient in both reading and mathematics.

This means that A \cap B = 0.65

78% were found to be proficient in mathematics

This means that B = 0.78

B = b + (A \cap B)

0.78 = b + 0.65

b = 0.13

85% of the students were found to be proficient in reading

This means that A = 0.85

A = a + (A \cap B)

0.85 = a + 0.65

a = 0.20

Proficient in at least one:

(A \cup B) = a + b + (A \cap B) = 0.20 + 0.13 + 0.65 = 0.98

What is the probability that the student is proficient in neither reading nor mathematics?

(A \cup B) + C = 1

C = 1 - (A \cup B) = 1 - 0.98 = 0.02

There is a 2% probability that the student is proficient in neither reading nor mathematics.

6 0
3 years ago
Please help?????????????????????
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Answer:

The answer is option (B)

Here is the explanation...

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2 years ago
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