Answer: (x,y) = (-1, 1)
This means that x = -1 and y = 1
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Explanation:
The first equation says that y is the same as 2x+3
That allows us to substitute y for 2x+3 in the second equation like so:
2x+5y = 3
2x+5( y ) = 3
2x + 5(2x+3) = 3 .... y replaced with 2x+3
2x+10x+15 = 3
12x+15 = 3
12x = 3-15
12x = -12
x = -12/12
x = -1
Then we'll substitute this into the first equation to find y
y = 2x+3
y = 2(-1) + 3 .... x replaced with -1
y = -2+3
y = 1
Together x = -1 and y = 1 pair up to form the ordered pair solution (x,y) = (-1,1)
If you were to graph y = 2x+3 and 2x+5y=3 on the same xy grid, then you should see that the two lines intersect at the location (-1,1). This is a visual way to determine the solution quickly through use of a graphing calculator.
Answer:
f(x) = -x³ + 3x² + 4x - 12
Step-by-step explanation:
f(x)=(x+2)(-x+3)(x-2)
Step 1. Use the difference of two squares
(x + 2)(x - 2) = x² - 4
f(x) = (-x + 3)(x² - 4)
Step 2. Long multiplication
x² - 4
<u>-x + 3 </u>
-x³ + 4x
<u> + 3x² - 12</u>
-x³ + 3x² + 4x - 12
f(x) = -x³ + 3x² + 4x - 12
Answer:
C)
Step-by-step explanation:
Perpendicular means negative reciprocal of the current slope.
And the negative reciprocal of -2 is 1/2.
Answer:
a.
Loan I's increase was 0.03 percentage points greater than Loan H's
Here, we want to find the diagonal of the given solid
To do this, we need the appropriate triangle
Firstly, we need the diagonal of the base
To get this, we use Pythagoras' theorem for the base
The other measures are 6 mm and 8 mm
According ro Pythagoras' ; the square of the hypotenuse equals the sum of the squares of the two other sides
Let us have the diagonal as l
Mathematically;
![\begin{gathered} l^2=6^2+8^2 \\ l^2\text{ = 36 + 64} \\ l^2\text{ =100} \\ l\text{ = }\sqrt[]{100} \\ l\text{ = 10 mm} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20l%5E2%3D6%5E2%2B8%5E2%20%5C%5C%20l%5E2%5Ctext%7B%20%3D%2036%20%2B%2064%7D%20%5C%5C%20l%5E2%5Ctext%7B%20%3D100%7D%20%5C%5C%20l%5Ctext%7B%20%3D%20%7D%5Csqrt%5B%5D%7B100%7D%20%5C%5C%20l%5Ctext%7B%20%3D%2010%20mm%7D%20%5Cend%7Bgathered%7D)
Now, to get the diagonal, we use the triangle with height 5 mm and the base being the hypotenuse we calculated above
Thus, we calculate this using the Pytthagoras' theorem as follows;
![\begin{gathered} d^2=5^2+10^2 \\ d^2\text{ = 25 + 100} \\ d^2\text{ = 125} \\ d\text{ = }\sqrt[]{125} \\ d\text{ = }11.2\text{ mm} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20d%5E2%3D5%5E2%2B10%5E2%20%5C%5C%20d%5E2%5Ctext%7B%20%3D%2025%20%2B%20100%7D%20%5C%5C%20d%5E2%5Ctext%7B%20%3D%20125%7D%20%5C%5C%20d%5Ctext%7B%20%3D%20%7D%5Csqrt%5B%5D%7B125%7D%20%5C%5C%20d%5Ctext%7B%20%3D%20%7D11.2%5Ctext%7B%20mm%7D%20%5Cend%7Bgathered%7D)
