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4 years ago

Classify the triangle based on angle measures.

Mathematics

1 answer:

arlik [135]4 years ago

3 0

This is an obtuse triangle because one angle of it is greater than 90 degrees :)

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Determine 57% of 289

krok68 [10]

Answer:

164.73

Step-by-step explanation:

1. convert 57% into a decimal by dividing it by 100.

--> 57/100 = 0.57

2. multiply the decimal by 289 to get your answer

--> 0.57(289) = 164.73

5 0

3 years ago

What is the value of x circle the correct answer 2\3 x =4

AfilCa [17]

Answer:

Step-by-step explanation:

(2/3) x = 4 Multiply both sides by 3

(2/3) x * 3 = 4 * 3 Combine

2x = 12 The 3's on the left cancel. Divide by 2

2x/2 = 12/2 Do the division

x =6

6 0

3 years ago

A relationship that has a constant rate of change represented by a line.

MaRussiya [10]

The answer is rate of change

7 0

3 years ago

Find the solution set. The solution set for -p2 − 11p = 0 is {}. (Separate the solutions with a comma.)

Umnica [9.8K]

$-p^2-11p=0\\
-p(p+11)=0\\
p=0 \vee p=-11$

$\{-11,0\}$

8 0

3 years ago

Read 2 more answers

A particle is moving with the given data. Find the position of the particle. a(t) = t2 − 3t + 9, s(0) = 0, s(1) = 20

sertanlavr [38]

Answer:

$s(t) = \frac{t^4}{12}-\frac{3t^3}{6}+\frac{9t^2}{2} +15.91667t$

Step-by-step explanation:

Integrating the expression that describes the acceleration of the particle gives us an expression for its velocity. Integrating the expression for its velocity, gives us the expression for its position:

$a(t) = t^2-3t+9\\\int{a(t)} \, dt=v(t) = \frac{t^3}{3}-\frac{3t^2}{2}+9t +A\\\int{v(t)} \, dt=s(t) = \frac{t^4}{12}-\frac{3t^3}{6}+\frac{9t^2}{2} +At+B$

Use the given values s(0) = 0 and s(s) = 20 to find the constants A and B:

$s(0) =0= 0-0-0 +A*0+B\\B=0\\ s(1) =20= \frac{1^4}{12}-\frac{3*1^3}{6}+\frac{9*1^2}{2} +A*1+0\\ A=15.91667\\\\s(t) = \frac{t^4}{12}-\frac{3t^3}{6}+\frac{9t^2}{2} +15.91667t$

8 0

4 years ago