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3 years ago

If log2= 0.3010. log3= 0.4771, log5= 0.6990. calculate log15??

Mathematics

1 answer:

Zepler [3.9K]3 years ago

8 0

Answer:

1.1761

Step-by-step explanation:

$log15 = log(3 \times 5) \\ = log3 + log5 \\ = 0.4771 + 0.6990 \\ = 1.1761 \\$

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<u>coordinates of the point are (2,6) and (3,4)</u>

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Solution given:

let the given point be A(1,8) and B(4,2).

P and Q are the two points on AB such that

AP=PQ=QB=k

now

comparing AP and PB

AP=k

PB=2k

ratio of AP and PB = $\frac{1k}{2k}$ = ratio 1:2

now

finding p

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$(m_1,m_2)=(1,2)$

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$(x_1,y_1)=(1,8)$

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now by using division formula

$(x,y)=(\frac{m_1x_2+m_2x_1}{m_1+m2},\frac{m_1y_2+m_2y_1}{m_1+m2})$

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Q divides AB

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$(x_1,y_1)=(1,8)$

$(x_2,y_2)=(4,2)$

$(m_1,m_2)=(2,1)$

by using division formula

$(a,b)=(\frac{m_1x_2+m_2x_1}{m_1+m2},\frac{m_1y_2+m_2y_1}{m_1+m2})$

$=(\frac{2*4+1*1}{2+1},\frac{2*2+1*8}{2+1})=(3,4)$

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3 years ago

If log2= 0.3010. log3= 0.4771, log5= 0.6990. calculate log15??​

If log2= 0.3010. log3= 0.4771, log5= 0.6990. calculate log15??