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3 years ago

Which is the graph of g(x) = [X +3]?

Mathematics

1 answer:

Daniel [21]3 years ago

4 0

Answer:

Step-by-step explanation:

just took it i got 100%

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Tickets to a show cost $5.50 for adults and $4.25 for students. A family is purchasing 2 adult tickets and 3 student tickets. Wh

MArishka [77]

Answer:

$23.75

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8 0

3 years ago

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Use the graph of f (x)=|x| to write an equation for the function repesented by the graph

NikAS [45]

See, please, the suggested explanation:
the equation is y= -|x+3|, where '-' means location of graph in the 3-d quarter, '+3' - the graph is moved to the left on 3 points.

7 0

3 years ago

Casey is trying to run a certain number of miles by the end of the month if Casey is 60% of the way to achieving our goals and s

astra-53 [7]

Answer:

40 miles is her goal.

Step-by-step explanation:

The problem says that 24 miles is 60% of her goal for that month.

You cab make a proportion with x being the goal for the whole month.

24/x = 6/10

You cross multiply and get:

6x = 24 x 10

6x = 240

x = 40

40 miles is the answer.

7 0

3 years ago

Operations with rational expressions

Scorpion4ik [409]

$$\frac{50-2 w^{2}}{3 w^{2}+9 w-30} \cdot \frac{w^{2}+5 w-14}{6 w-30}=-\frac{w+7}{9}$

Solution:

Given expression:

$$\frac{50-2 w^{2}}{3 w^{2}+9 w-30} \cdot \frac{w^{2}+5 w-14}{6 w-30}$

To solve the given expression:

First simplify: $\frac{50-2 w^{2}}{3 w^{2}+9 w-30}$

$$\frac{50-2 w^{2}}{3 w^{2}+9 w-30}=-\frac{2(w+5)(w-5)}{3(w-2)(w+5)}$

Cancel the common factor (w + 5).

$$=-\frac{2(w-5)}{3(w-2)}$

Now substitute this in the given expression.

$$\frac{50-2 w^{2}}{3 w^{2}+9 w-30} \cdot \frac{w^{2}+5 w-14}{6 w-30}=-\frac{2(w-5)}{3(w-2)} \cdot \frac{w^{2}+5 w-14}{6 w-30}$

Multiply the fractions $\frac{a}{b} \cdot \frac{c}{d}=\frac{a \cdot c}{b \cdot d}$

$$=-\frac{2(w-5)\left(w^{2}+5 w-14\right)}{3(w-2)(6 w-30)}$

Factor the denominator $3(w-2)(6 w-30) =18(w-2)(w-5)$

$$=-\frac{2(w-5)\left(w^{2}+5 w-14\right)}{18(w-2)(w-5)}$

Cancel the common factor 2(w – 5).

$$=-\frac{w^{2}+5 w-14}{9(w-2)}$

Factor the numerator $w^{2}+5 w-14=(w-2)(w+7)$

$$=-\frac{(w-2)(w+7)}{9(w-2)}$

Cancel the common factor (w – 2).

$$=-\frac{w+7}{9}$

$$\frac{50-2 w^{2}}{3 w^{2}+9 w-30} \cdot \frac{w^{2}+5 w-14}{6 w-30}=-\frac{w+7}{9}$

3 0

3 years ago

Solve the linear equation.<br> 7x+10= 1/3(12x-3)+14x

pychu [463]

7x+10=1/3×(12x-3)+14x

7x+10=1/3×3(4x-1)+14x

7x+10=(4x-1)+14x

7x+10=4x-1+14x

7x+10=18x-1

7x-18x=-1-10

-11x=-11

x=1

5 0

4 years ago

Read 2 more answers