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katen-ka-za [31]
3 years ago
8

Which is the equation of a circle that has a center of (-1, 3) and passes through the point (3, 6)?

Mathematics
1 answer:
tatiyna3 years ago
6 0

Answer:

( x + 1)^2 + ( y - 3)^2 = 25

Step-by-step explanation:

The equation of the circle with a center and a point

( x - a) ^2 + ( y - b) ^2 = r^2

( a , b) - center of the circle

( x , y) - any point on the circle

r^2 - radius

( -1 , 3) - ( center) - ( a, b)

a = -1

b = 3

( 3 , 6) - ( point) - ( x, y)

x = 3

y = 6

Step 1: substitute the center into the equation

( x -(-1)^2 + ( y - 3)^2 = r^2

( x + 1)^2 + ( y - 3)^2 = r^2

Step 2: sub the point into the equation

( x + 1)^2 + (y - 3)^2 = r^2

( 3 + 1)^2 + ( 6 - 3)^2 = r^2

4^2 + 3^2 = r^2

16 + 9 = r^2

25 = r^2

Step 3: sub the radius into the equation

( x + 1)^2 + ( y - 3)^2 = r^2

( x + 1)^2 + (y - 3)^2 = 25

Therefore, the equation of the circle is

( x + 1)^2 + (y - 3)^2 = 25

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What’s the domain and range?<br><br> An airplane travels at 565 mph.
viktelen [127]

Answer:

<u>Domain:</u>

The domain of this can be any value between 0 to 565 miles per hour

<u>Range:</u>

The reasonable range can be the distance traveled which can be from 0 to 13,560 miles (no plane travel is longer than 24 hours, we assume).

Step-by-step explanation:

Domain is the input, set of x values for the function.

Range is the output, set of y values for the function.

This isn't a function essentially, but it is given that an Airplane travels at 565 miles per hour.

<em>We can say that the domain will be the speed of the airplane and the range would be the distance it travels.</em>

<em />

<u>Domain:</u>

The domain of this can be any value between 0 to 565 miles per hour

<u>Range:</u>

The reasonable range can be the distance traveled which can be from 0 to (565*24=13,560 miles) 13,560 miles (no plane travel is longer than 24 hours, we assume).

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If the three angles of a quadrilateral are 120, 130, 100 then what is the fourth angle?
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Step-by-step explanation:

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