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solniwko [45]
4 years ago
6

Can someone please help me for this question 43 pls! I really need to know how I can solve this question!!!!!

Mathematics
1 answer:
fiasKO [112]4 years ago
8 0
630 you take the 14.00 an hour she was making and multiply it by 45
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Find the quotient of 1 1/5 and 3 4/5
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Find the length of the arc on a circle with a radius of 2.4 kilometers and is intercepted by a central angle measuring 150°. lea
Kaylis [27]

If the radius of the circle exists 2.4 kilometers and is intercepted by a central angle measuring 150° then the length of the arc exists 5π inches.

<h3>What was the relation between the central angle and its intercepted arc?</h3>
  • If the vertex of an angle exists in the center of the circle and the two sides of the angle are radii in the circle, then this angle exists named a central angle.
  • Each central angle exists subtended by the opposite arc, the name of the arc exists the starting point and the finish point of the angle.
  • There exists a relation between the central angle and its subtended arc the measure of the central angle equals half the measure of its subtended arc.
  • The length of the subtended arc relies on the measurement of its central angle and the length of the radius and the measure of the arc.
  • The measurement of the circle exists at 360°.
  • The length of the circle exists at 2πr.

The radius of the circle r = 2.4 kilometers

The measure of the central angle exists at 150°.

The length of the arc = central angle/360 × 2πr

The length of the arc = 150°/360° × 2 × π × 2.4 = 2π

The length of the arc exists 2π kilometers.

To learn more about arc length refer to:

brainly.com/question/11134371

#SPJ4

4 0
2 years ago
Samuel starts off with 125 to spend on shirts and ties samuel buys 3 shirts for 24.50 each ties cost 14.50 how many toes can sam
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Samuel could buy 3 ties.

3 0
3 years ago
REALLY in need of help, Solve right triangle. Round decimal answers to the nearest tenth. Please help :)
dybincka [34]

Answer:

I have attached the work for your problem below.

Please see the attachment.

I hope it helps.

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3 years ago
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