What is X/3=3X-15/4 Please help me thanks
1 answer:
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Answer:
292,968
Step-by-step explanation:
As we know,
Sum of a geometric sequence (S) =
where,
a = first term of sequence,
r = the constant ratio,
n = number of terms in sequence.
So, according to the question,
a = 3,
r = 5,
n = 8.
by substituting the values in the above formula, we get;
⇒
⇒
So hmm notice the picture below
the dividend, has all terms, already in descending order
the divisor, is missing one, the "x", so that means is 0x, so we add it
the idea is, you want to knock down the leftmost term in the dividend
so... to do say the first term.. then, we need to find say
some value to multiply times 3x² to mimick or resemble 6x⁴
so.. that value is 2x²....the we slap a -( ..... ) to the whole product, thus in effect hosing 6x⁴ with a 6x⁴ - 6x⁴ or 0x⁴ or 0
and so on
the dividend, has all terms, already in descending order
the divisor, is missing one, the "x", so that means is 0x, so we add it
the idea is, you want to knock down the leftmost term in the dividend
so... to do say the first term.. then, we need to find say
some value to multiply times 3x² to mimick or resemble 6x⁴
so.. that value is 2x²....the we slap a -( ..... ) to the whole product, thus in effect hosing 6x⁴ with a 6x⁴ - 6x⁴ or 0x⁴ or 0
and so on