Answer:
292,968
Step-by-step explanation:
As we know,
Sum of a geometric sequence (S) =
where,
a = first term of sequence,
r = the constant ratio,
n = number of terms in sequence.
So, according to the question,
a = 3,
r = 5,
n = 8.
by substituting the values in the above formula, we get;
⇒
Let's simplify step-by-step.
3t−3+6t2+4t+13−8t2+11t−1
=3t+−3+6t2+4t+13+−8t2+11t+−1
Combine Like Terms:
=(6t2+−8t2)+(3t+4t+11t)+(−3+13+−1)
=−2t2+18t+9
It is to be solved by reminder thoremf(x)/(x-k) will have reminder f(k), so, f(2) = 5*(2^4) + 8 *(2^3) +4* (2^2) -5(2) +67
=5*16 + 8*8 +4*4 -5*2 +67 =80 + 64 + 16 -10 +67
= 217
