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3 years ago

I need help i will give the brainliest!

Mathematics

1 answer:

eimsori [14]3 years ago

5 0

Answer:

1)-6a+-48

2)4+36x

3)-30n+18

4)18m+20

5)32-24n

6)-8b-32

7)5-35n

8)-6x+-24

9)15m-30

10)24p+-28

11)5b-5

12)5x+45

Step-by-step explanation:

Distributive property, Hope this helps!

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Whats the process you would use to find the volume of the shipping box

iren2701 [21]

Answer:

Find length, width and height of the shipping box.

Step-by-step explanation:

In order to find the volume of the shipping box, you should measure the lengths of all its dimensions, that is length, width and height.

7 0

3 years ago

mr.browns salary is 32,000 and imcreases by $300 each year, write a sequence showing the salary for the first five years when wi

chubhunter [2.5K]

Hello!

We have the following data:

a1 (first term or first year salary) = 32000

r (ratio or annual increase) = 300

n (number of terms or each year worked)

We apply the data in the Formula of the General Term of an Arithmetic Progression, to find in sequence the salary increases until it exceeds 34700, let us see:

formula:

$a_n = a_1 + (n-1)*r$

* second year salary

$a_2 = a_1 + (2-1)*300$

$a_2 = 32000 + 1*300$

$a_2 = 32000 + 300$

$\boxed{a_2 = 32300}$

* third year salary

$a_3 = a_1 + (3-1)*300$

$a_3 = 32000 + 2*300$

$a_3 = 32000 + 600$

$\boxed{a_3 = 32600}$

* fourth year salary

$a_4 = a_1 + (4-1)*300$

$a_4 = 32000 + 3*300$

$a_4 = 32000 + 900$

$\boxed{a_4 = 32900}$

* fifth year salary

$a_5 = a_1 + (5-1)*300$

$a_5 = 32000 + 4*300$

$a_5 = 32000 + 1200$

$\boxed{a_5 = 33200}$

We note that after the first five years, Mr. Browns' salary has not yet surpassed 34700, let's see when he will exceed the value:

* sixth year salary

$a_6 = a_1 + (6-1)*300$

$a_6 = 32000 + 5*300$

$a_6 = 32000 + 1500$

$\boxed{a_6 = 33500}$

* seventh year salary

$a_7 = a_1 + (7-1)*300$

$a_7 = 32000 + 6*300$

$a_7 = 32000 + 1800$

$\boxed{a_7 = 33800}$

* eighth year salary

$a_8 = a_1 + (8-1)*300$

$a_8 = 32000 + 7*300$

$a_8 = 32000 + 2100$

$\boxed{a_8 = 34100}$

* ninth year salary

$a_9 = a_1 + (9-1)*300$

$a_9 = 32000 + 8*300$

$a_9 = 32000 + 2400$

$\boxed{a_9 = 34400}$

* tenth year salary

$a_{10} = a_1 + (10-1)*300$

$a_{10} = 32000 + 9*300$

$a_{10} = 32000 + 2700$

$\boxed{a_{10} = 34700}$

we note that in the tenth year of salary the value equals but has not yet exceeded the stipulated value, only in the eleventh year will such value be surpassed, let us see:

* eleventh year salary

$a_{11} = a_1 + (11-1)*300$

$a_{11} = 32000 + 10*300$

$a_{11} = 32000 + 3000$

$\boxed{\boxed{a_{11} = 35000}}\end{array}}\qquad\checkmark$

Respuesta:

In the eleventh year of salary he will earn more than 34700, in the case, this value will be 35000

________________________

¡Espero haberte ayudado, saludos... DexteR! =)

7 0

3 years ago

I need urgent help with this one

Serhud [2]

let the unknown answer be equal to f

.-2.1 - f = -3/2

-f = -3/2 + 2.1

-f = 0.6

f = -0.6

5 0

3 years ago

Read 2 more answers

How many kids are there in the US

alexira [117]

Answer:

74.2 million children under the age of 18

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

When 13 is subtracted from the sum of 2 consecutive numbers the answer is 18 what are the consecutive numbers?

Hitman42 [59]

Let x = the first number
x+1 = the second number

The sum of our two numbers is therefore: x + (x+1)

When you subtract 13 from the above you get 18 left over.

So our equation is:

x + (x+1) - 13 = 18

Now we can just solve for x:

x + (x+1) = 31

2x + 1 = 31

2x = 30

x = 15

So our first number is 15 and our second number must be 16.

7 0

4 years ago