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geniusboy [140]

3 years ago

9

BASKETBALL After Game 1, Felicia had scored 14 points. After Game 5, she had scored a total of 82 points for the season. After G

ame 10, she had scored 129 points. Graph the data with the game number on the horizontal axis and the number of points on the vertical axis. Connect the points using two different line segments.

1 answer:

Stella [2.4K]3 years ago

4 0

Let $p$ represents the number of points scored in $n$ number of games.

So, the graph, the number of games, n is on the horizontal axis and the points scored, p, is on the vertical axis.

After Game 1, the point scored is 14,

so, the first point, $P_1$ , on the graph is

$P_1=(1,14)$

After Game 5, the point scored is 82,

so, the second point, $P_2$ , on the graph is

$P_2=(5,82).$

After Game 10, the point scored is 129,

so, the second point, $P_2$ , on the graph is

$P_2=(10,129)$

First, represent all the three points, $P_1, P_2$ and $P_3$ , on the graph, then connect $P_1- P_2$ and $P_2 - P_3$ as shown in the figure.

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I am lost on "Graph y< -3|x-1| please help!

Sindrei [870]

1) |x| is the absolute value function. Its vertex is at (0,0).

2) |x-1| has the same graph as does y = |x|, except that the vertex is shifted 1 unit to the left.

3) -3|x-1| has the same graph as the previous result, except that we must reflect the previous graph in the x-axis.

4) Replace the solid lines you used in this graph with dashed ones.

5) Shade the area beneath y = -3|x-1|

In summary:

the desired graph is the shaded area below the inverted v-shaped graph of

y = -3|x-1|. Its vertex is at (-1,0).

6 0

4 years ago

What is the probability that a randomly selected member of a normally distributed population will lie more than 1.8 standard dev

Helen [10]

Answer:

$P(X> \mu +1.8\sigma)=P(\frac{X-\mu}{\sigma}>\frac{\mu +1.8\sigma-\mu}{\sigma})=P(Z>1.8)$

And we can find this probability using the complement rule:

$P(z>1.8)=1-P(z$

And using the normal standard distirbution table or excel we got:

$P(z>1.8)=1-P(z$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

Let X the random variable that represent the variable if interest of a population, and for this case we know the distribution for X is given by:

$X \sim N(\mu,\sigma)$

We are interested on this probability

$P(X>\mu +1.8 \sigma)$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\sigma}$

If we apply this formula to our probability we got this:

$P(X> \mu +1.8\sigma)=P(\frac{X-\mu}{\sigma}>\frac{\mu +1.8\sigma-\mu}{\sigma})=P(Z>1.8)$

And we can find this probability using the complement rule:

$P(z>1.8)=1-P(z$

And using the normal standard distirbution table or excel we got:

$P(z>1.8)=1-P(z$

5 0

3 years ago

Mustafa, Heloise, and Gia have written more than a combined total of 222222 articles for the school newspaper. Heloise has writt

baherus [9]

Answer:

The Inequality For determining number of equation written by Mustafa for school paper is $x+\frac{1}{4}x+ \frac{3}{2}x\geq 22$ .

Mustafa has written more than 8 articles.

Step-by-step explanation:

Given:

Combined Total Number of articles = 22

Let the number of articles written by Mustafa be 'x'.

Now Given:

Heloise has written $\frac{1}{4}$ as many articles as Mustafa has.

Number of article written by Heloise = $\frac{1}{4}x$

Gia has written $\frac{3}{2}$ as many articles as Mustafa has.

Number of article written by Gia = $\frac{3}{2}x$

Now we know that;

The sum of number of articles written by Mustafa and Number of article written by Heloise and Number of article written by Gia is greater than or equal to Combined Total Number of articles.

framing in equation form we get;

$x+\frac{1}{4}x+ \frac{3}{2}x\geq 22$

Hence the Inequality For determining number of equation written by Mustafa for school paper is $x+\frac{1}{4}x+ \frac{3}{2}x\geq 22$ .

Now Solving the Inequality we get;

Taking LCM for making the denominator common we get:

$\frac{x\times 4}{4}+\frac{1\times1}{4\times1}x+ \frac{3\times2}{2\times2}x\geq 22\\\\\frac{4x}{4}+ \frac{x}{4}+\frac{6x}{4}\geq 22\\\\\frac{4x+x+6x}{4} \geq 22\\\\11x\geq 22\times4\\\\11x\geq 88\\\\x\geq \frac{88}{11} \\\\x\geq 8$

Hence Mustafa has written more than 8 articles.

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3 years ago

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lys-0071 [83]

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8 0

3 years ago

Oliver reads 28 1/2 pages of a book in 1 1/6 hours. Express his reading speed in pages per hour

Inessa05 [86]

Hello there

in order to find the answer you need to multiply 28.5 by 1 1/6

you get 171/7

the answer is 24.4 pages

thank you

hope this helps

Best Regards Queen Z

3 0

3 years ago

Read 2 more answers