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jeyben [28]
3 years ago
11

Separate 46 into 2 parts so that 1 part is 1 more than twice as much as the first part. Find each part. show work

Mathematics
1 answer:
JulsSmile [24]3 years ago
3 0

Answer:

x=31

y=15

Step-by-step explanation:

let x and y be the 2 part

x+y=46

x-2y=1 ⇒ x=1+2y

substitute :

1+2y+y=46

3y=46-1

3y=45 ⇒ y=45/3=15

x-2y=1

x-2(15)=1 ⇒ x=1+30 ⇒x=31

x= 2 times y(15)+1

y=15

31+15=46

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