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aksik [14]
3 years ago
14

CEA is a right angle and EB bisects CEA

Mathematics
1 answer:
Serga [27]3 years ago
8 0
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When Cullen cleaned behind his dresser, he found 73 cents, all in nickels and pennies. There were 25 coins. How many were nickel
Georgia [21]
Let n = number of nickels, and p = number of pennies.
The number of coins is 25, so we get this equation.
n + p = 25

The value of the coins is 0.05 per nickel, and 0.01 per penny.
0.05n + 0.01p = 0.73

Now you have a system of equations.

n + p = 25
0.05n + 0.01p = 0.73

Solve the first equation for n:
n = 25 - p

Now substitute into the second equation.

0.05(25 - p) + 0.01p = 0.73

1.25 - 0.05p + 0.01p = 0.73

-0.04p = -0.52

p = 13

There were 13 pennies.
Now we substitute 13 for p in n + p = 25 to find out the number of nickels.

n + 13 = 25
n = 12

There are 13 pennies and 12 nickels.

Check: 13 pennies and 12 nickels does total 25 coins.
13 * 0.01 + 12 * 0.05 = 0.13 + 0.60 = 0.73
The value is $0.73.
Our answer is correct.
5 0
3 years ago
A charity fair raised $6,000 by selling 500 lottery tickets. There were two types of lottery tickets: A tickets cost $10 each, a
jeka94
The ans is option number D


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Write 5/10 in three equivalent forms. with Decimals please
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1/2 2/4 3/6
0.5 0.50 0.500
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Complete the following statement. Write
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The answer is the second option-always
4 0
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382 3/10 - 191 87/100=
frosja888 [35]
382  \frac{3}{10}  - 191  \frac{87}{100} =(382 + \frac{3}{10} ) - (191 + \frac{87}{100}) =\\\\=382 + \frac{30}{100} -191- \frac{87}{100} =382  -191+ \frac{30}{100}- \frac{87}{100} =\\\\=191+ \frac{30}{100}- \frac{87}{100} =190+ \frac{100}{100}+ \frac{30}{100}- \frac{87}{100} =\\\\=190+\frac{130}{100}- \frac{87}{100} =190+\frac{43}{100}=190\frac{43}{100}\\\\\\382  \frac{3}{10}  - 191  \frac{87}{100} =382.3  - 191.87 =382.3  - 191-0.87 =191.3-0.87=\\\\=190+1.3-0.87=190+0.43=190.43
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3 years ago
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