The end behavior of the function is the one in option C.
<em>"One end increases and one end decreases"</em>
<h3>
What can we say about the end behavior?</h3>
Here we have the function:
f(x) = -ln(2x) + 4.
Remember that for the natural logarithm, as x tends to zero the function tends to negative infinity.
And as x tends to infinity, the natural logarithm tends to infinity.
So, for our function where we have a negative sign before the logarithm, as x tends to zero the function tends to infinity and as x tends to infinity the function tends to zero.
Then the correct option is C:
<em>"One end increases and one end decreases"</em>
If you want to learn more about end behaviors:
<em>brainly.com/question/1365136</em>
<em>#SPJ1</em>
Answer:
Step-by-step explanation:
1. Lets transfer ounces ⇄ to Millimeters.
2. Lets multiply.
is: .
Hope this helps :)
Recall some identities:
tan(x) = sin(x) / cos(x)
cos(x + y) = cos(x) cos(y) - sin(x) sin(y)
cos(x - y) = cos(x) cos(y) + sin(x) sin(y)
sin(x - y) = sin(x) cos(y) - cos(x) sin(y)
This means we have
• cos²(90° - x) = [cos(90°) cos(x) + sin(90°) sin(x)]²
… = sin²(x)
• tan(180° - x) = sin(180° - x) / cos(180° - x)
… = [sin(180°) cos(x) - cos(180°) sin(x)] / [cos(180°) cos(x) + sin(180°) sin(x)]
… = sin(x) / (-cos(x))
… = -tan(x)
(and we also get sin(180° - x) = sin(x))
• cos(180° + x) = cos(180°) cos(x) - sin(180°) sin(x)
… = -cos(x)
So, the given expression reduces to
sin²(x) (-tan(x)) (-cos(x)) / sin(x) = sin²(x)
since tan(x) and cos(x)/sin(x) = 1/tan(x) will cancel.
