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3 years ago

Can someone answer this please?

Mathematics

1 answer:

algol [13]3 years ago

8 0

Answer:find it online

Step-by-step explanation:

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Choose the graph which represents the solution to the inequality. 12x + 4 ≤ -8

user100 [1]

Answer:

Step-by-step explanation:

Steps:

$12x+4-4\leq -8$

Subtract 4 from both sides:

$12x+4-4\leq -8-4$

Simplify:

$12x\leq \frac{-12}{12}$

Divide both sides by 12:

$\frac{12x}{12} \leq \frac{-12}{12}$

Simplify:

$x\leq -1$

3 0

3 years ago

If an object is dropped from a height of 96ft, the function h(t) = -62 + 96 gives the height of the object after t seconds. When

Shalnov [3]

Answer:

Step-by-step explanation:Since we want to know how much time elapsed since the object was launched until it ht the ground. At the ground, the height is 0.

Therefore the equation h(t) = 80t – 16t2 becomes 0= 80t – 16t2

Solving the equation for t gives 80t =16t2 or 16t=80 or t=5sec

The object hits the ground 5 seconds after it is launched.

7 0

2 years ago

Gravel is being dumped from a conveyor belt at a rate of 15 ft3/min, and its coarseness is such that it forms a pile in the shap

gayaneshka [121]

Answer:

0.13 ft/min

Step-by-step explanation:

We are given that

$\frac{dV}{dt}=15ft^3/min$

We have to find the increasing rate of change of height of pile when the pile is 12 ft high.

Let d be the diameter of pile

Height of pile=h

d=h

Radius of pile,r= $\frac{d}{2}=\frac{h}{2}$

Volume of pile= $\frac{1}{3}\pi r^2 h=\frac{1}{12}\pi h^3$

$\frac{dV}{dt}=\frac{1}{4}\pi h^2\frac{dh}{dt}$

h=12 ft

Substitute the values

$15=\frac{1}{4}\pi(12)^2\frac{dh}{dt}$

$\frac{dh}{dt}=\frac{15\times 4}{\pi(12)^2}$

$\frac{dh}{dt}=0.13ft/min$

7 0

3 years ago

if 2/5 of a ton of concrete covers 5/6 of a wall, how many tons of concrete are required to cover the entire wall?

Valentin [98]

Your answer would be 12/25 tons. If you set up a proportion 2/5 X
   -------- = -------
      5/6   1
Solve your proportion.

8 0

3 years ago

Read 2 more answers

What are the ordered pairs of the

9966 [12]

Start by writing the system down, I will use $y$ to represent $f(x)$

$y=x^2-5x+3\wedge y=-3$

Substitute the fact that $y=-3$ into the first equation to get,

$-3=x^2-5x+3$

Simplify into a quadratic form ( $ax^2+bx+c=0$ ),

$x^2-5x+6=0$

Now you can use Vieta's rule which states that any quadratic equation can be written in the following form,

$x^2+x(m+n)+mn=0$

which then must factor into

$(x+m)(x+n)=0$

And the solutions will be $m,n$ .

Clearly for small coefficients like ours $5,6$ , this is very easy to figure out. To get 5 and 6 we simply say that $m=3, n=2$ .

This fits the definition as $5=3+2$ and $6=2\cdot3$ .

So as mentioned, solutions will equal to $m=3, n=2$ but these are just x-values in the solution pairs of a form $(x,y)$ .

To get y-values we must substitute 3 for x in the original equation and then also 2 for x in the original equation. Luckily we already know that substituting either of the two numbers yields a zero.

So the solution pairs are $(2,0)$ and $(3,0)$ .

Hope this helps :)

5 0

2 years ago