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alexira [117]
3 years ago
10

Can u guys pretty please help

Mathematics
1 answer:
erastova [34]3 years ago
7 0
It should be A and D, no promises
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(Ill give brainliest and extra points if u help)
Marina CMI [18]

Answer:

NO.

Step-by-step explanation:

If Robert has a total of 3,084 baseball cards, and each sleeve can contain 12 cards, we can figure out how many sleeves he would need by dividing the two. When we divide 3,084 by 12, we find that it equals 257. Robert figured he'd need 250. His conclusion is, thus, 7 cards deficient.

6 0
3 years ago
Read 2 more answers
16/250, 6.5% and 0.062 from least to greatest
harina [27]
0.062,16/250 and 6.5%
3 0
3 years ago
The ravens won three more games than they lost. they played 96 games. how many games did they win
ololo11 [35]

divide 96 by 2  which gives you 48 and subtract 3 since they lost 3 which is 45. you the subtract 96 from 45 which gives you 51 which is the answer

6 0
4 years ago
In a random sample of cars driven at low altitudes, of them exceeded a standard of grams of particulate pollution per gallon of
Orlov [11]

Complete question is;

In a random sample of 370 cars driven at low altitudes, 43 of them exceeded a standard of 10 grams of particulate pollution per gallon of fuel consumed. In an independent random sample of 80 cars driven at high altitudes, 23 of them exceeded the standard. Can you conclude that the proportion of high-altitude vehicles exceeding the standard is greater than the proportion of low-altitude vehicles exceeding the standard at an level of significance? Group of answer choices

Answer:

Yes we can conclude that there is enough evidence to support the claim that the proportion of high-altitude vehicles exceeding the standard is greater than the proportion of low-altitude vehicles exceeding the standard (P-value = 0.00005).

Step-by-step explanation:

This is a hypothesis test for the difference between the proportions.

The claim is that the proportion of high-altitude vehicles exceeding the standard is greater than the proportion of low-altitude vehicles exceeding the standard.

Then, the null and alternative hypothesis are:

H0 ; π1 - π2 = 0

H1 ; π1 - π2 < 0

The significance level would be established in 0.01.

The random sample 1 (low altitudes), of size n1 = 370 has a proportion of;

p1 = x1/n1

p1 = 43/370

p1 = 0.116

The random sample 2 (high altitudes), of size n2 = 80 has a proportion of;

p2 = x2/n2

p2 = 23/80

p2 = 0.288

The difference between proportions is pd = (p1-p2);

pd = p1 - p2 = 0.116 - 0.288

pd = -0.171

The pooled proportion, we need to calculate the standard error, is:

p = (x1 + x2)/(n1 + n2)

p = (43 + 23)/(370 + 80)

p = 66/450

p = 0.147

The estimated standard error of the difference between means is computed using the formula:

S_(p1-p2) = √[((p(1 - p)/n1) + ((p(1 - p)/n2)]

1 - p = 1 - 0.147 = 0.853

Thus;

S_(p1-p2) = √[((0.147 × 0.853)/370) + ((0.147 × 0.853)/80)]

S_(p1-p2) = 0.044

Now, we can use the formula for z-statistics as;

z = (pd - (π1 - π2))/S_(p1-p2)

z = (-0.171 - 0)/0.044

z = -3.89

Using z-distribution table, we have the p-value = 0.00005

Since the P-value of (0.00005) is smaller than the significance level (0.01), then the effect is significant.

We conclude that The null hypothesis is rejected.

Thus, there is enough evidence to support the claim that the proportion of high-altitude vehicles exceeding the standard is greater than the proportion of low-altitude vehicles exceeding the standard.

6 0
3 years ago
What is the estimated product of 1.39 x 6.76?
qwelly [4]

Answer:

7

Step-by-step explanation:

5 0
3 years ago
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