Answer:
The length of side of largest square is 15 inches
Step-by-step explanation:
The given suares are when joined in the way as shown in picture their sides form a right agnled triangle.
Area of square 1 and perimeter of square 2 will be used to calculate the sides of the triangle.
So,
<u>Area of square 1: 81 square inches</u>

<u>Perimeter of square 2: 48 inches</u>

We can see that a right angled triangle is formed.
Here
Base = 12 inches
Perpendicular = 9 inches
And the side of largest square will be hypotenuse.
Pythagoras theorem can be used to find the length.

Hence,
The length of side of largest square is 15 inches
Answer:
f(x) is shifted 7 units to the right.
Hello from MrBillDoesMath!
Answer:
72
Discussion:
Total Surface area = area of pyramid base + 4 ( area of triangular face)
In our case this becomes
4*4 + 4( (1/2) (4)(7) ) =
= 16 + (2)(4)(7)
= 16 + 56
= 72
which is the first choice.
Note: the area of a triangular face was computed using (1/2) b h, which in our case is
(1/2) (4) (7)
Thank you,
MrB
I think 15 is the answer hope this helps