Question

Plz help, I don’t mean to hit the first answer

Answer 1

$\frac{1}{3}\\\\\frac{2}{3}\\\\\frac{0}{12}$

Step-by-step explanation:

Red blocks = 4, White blocks = 4, Blue blocks = 4, Green blocks = 0

Total blocks = 4 + 4 + 4 = =12

1)

Probability of picking a red block

$=\frac{No. \: of\: red\: blocks}{Total\: blocks} =\frac{4}{12}=\frac{1}{3}$

2)

Probability of not picking a red block

$=\frac{No. \: of\: white\: and \: blue\: blocks}{Total\: blocks} \\\\=\frac{4+4}{12}=\frac{8}{12}=\frac{2}{3}$

3)

Probability of picking a green block

$=\frac{No. \: of\: green \: blocks}{Total\: blocks} =\frac{0}{12}$