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Masteriza [31]
3 years ago
7

Cual es la suma de los ángulos externos de un triángulo​

Mathematics
1 answer:
mr_godi [17]3 years ago
4 0
“what is the sum of the angles of a triangle” 180 degrees
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If x / 3 equals 6 then x equals
sleet_krkn [62]

Answer: X = 18

Step-by-step explanation:

Crossmultiply

8 0
4 years ago
What is the range of this function?
Rzqust [24]

Greetings.

The range is the set of y-value.

The range starts from the minimum point to maximum point.

Our minimum point starts at 0 and maximum point starts less than infinity.

Therefore the range is 0<=y<+inf

However, we do not often write that, although it is right.

Therefore we write as y≥0

Thus, the answer is B choice.

5 0
3 years ago
What is they square root of 36
Bogdan [553]

Answer:

6

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Write a quadratic equation with -4 and 3/2 as it’s roots. Write the equation in the form ax^2 + bx + c = 0, where a, b, and c ar
jonny [76]

9514 1404 393

Answer:

  2x² +5x -12 = 0

Step-by-step explanation:

When p and q are roots of a quadratic, its factored form can be written as ...

  (x -p)(x -q) = 0

Here, the roots are given as -4 and 3/2, so the factored form would be ...

  (x -(-4))(x -(3/2) = 0

Multiplying by 2 gives us ...

  (x +4)(2x -3) = 0

Expanding the product, we find the desired quadratic is ...

  2x² +5x -12 = 0

5 0
3 years ago
Miki has 104 nickels and 88 dimes. She wants to divide her coins into groups where each group has the same number of nickels and
pochemuha

Given :

Miki has 104 nickels and 88 dimes.

She wants to divide her coins into groups where each group has the same number of nickels and the same number of dimes.

To Find :

Largest number of groups she can have .

Solution :

In the given question we need to find the largest number of groups she can have i.e we have to find the LCM of 104 and 88 .

Now , factorizing both of them , we get :

104=1\times 2\times 2\times 2\times 13

88=1\times 2\times 2\times 2\times 11

Form above , we can say that common factors are :

HCF=2\times 2\times 2=8

Therefore , the largest number of groups she can have is 8 .

Hence , this is the required solution .

6 0
3 years ago
Read 2 more answers
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