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Alenkasestr [34]
4 years ago
10

Hey guys I have more questions comming soon​

Mathematics
2 answers:
gavmur [86]4 years ago
8 0

Answer:

25a-40b-10 is your answer, hope this helped :)

Step-by-step explanation:

V125BC [204]4 years ago
3 0
I believe the answer is 25a—40b —10
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Ron used 121 congruent equilateral triangles with 2 cm side lengths to form one large equilateral triangle. What is the perimete
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The number of smaller triangles along one side of the larger triangle is the square root of the total number of triangles. The perimeter of the large triangle is ...
  3*(2 cm)*√121 = 66 cm
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4 years ago
Verify that ABC is a right triangle by showing that the sum of the areas of the squares formed with sides a and b is equal the a
sweet-ann [11.9K]

Step-by-step explanation:

Pythagoras' theorem shows that a^2+b^2=c^2. Not sure how else to help here.

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3 years ago
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A store manager sets up a cardboard display to advertise a new brand of perfume the display is a square peer amid whose base is
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This answer is most likely wrong, but this is what I had gotten.
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3 years ago
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Diego wants to have $1,000,000 in 5 years. He plans to invest $250,000 to start and make yearly payments of $125,000 to the acco
julia-pushkina [17]

Answer:

Yes

Step-by-step explanation:

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So in 5 years he'll have about $1,662,500 using simple intrest but with compound it'd be more like 2mil

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5 0
2 years ago
Express with radical signs instead of fractional exponents. Rationalize the denominator.
CaHeK987 [17]

x^{\frac{1}{2}} = \sqrt[2]{x} and 3^{-\frac{1}{2}} = \frac{1}{3^{\frac{1}{2}} } = \frac{1}{\sqrt[2]{3}} so

3^{-\frac{1}{2}} x^{\frac{1}{2}} = \frac{1}{\sqrt{3}} \cdot \sqrt{x}  = \frac{\sqrt{x}}{\sqrt{3}}

and you rationalize denominator by multiplying numerator and denominatr by \sqrt{3} so that gives--

\frac{\sqrt{x}}{\sqrt{3}} \cdot \frac{\sqrt{3}}{\sqrt{3}} = \frac{\sqrt{3x}}{3}

Your answer is \frac{\sqrt{3x}}{3}

5 0
3 years ago
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