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Natalija [7]
3 years ago
13

A community organizes a phone tree in order to alert each family of emergencies. In the first stage, one person calls five famil

ies. In the second stage, each of the five families calls another five families, and so on. How many stages need to be reached before 19,530 families or more have been called?
Mathematics
1 answer:
masya89 [10]3 years ago
6 0
Answer: It will take 7 stages for all 19,530 families to be called.

In the first stage, only 5 families are called.

In the second stage, we would have 5 x 5 = 25 families being called.

In the third stage, we would have 5 x 5 x 5 = 125 families being called.
We can use exponents to finish the list and see when our goal is reached.

4th stage: 5^4 = 625

5th stage: 5^5 = 3125

6th stage: 5^6 = 15625

7th stage: 5^7 = 78,125
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A soft drink machine outputs a mean of 24 ounces per cup. The machine's output is normally distributed with a standard deviation
Arisa [49]

Answer:

P(21

And we can find the probability with this difference

P(-1

And using the normal standard distribution or excel we got:

P(-1

Step-by-step explanation:

Let X the random variable that represent the soft drink machine outputs of a population, and for this case we know the distribution for X is given by:

X \sim N(24,3)  

Where \mu=24 and \sigma=3

We want to find this probability:

P(21

The z score is given by:

z=\frac{x-\mu}{\sigma}

Using this formula we got:

P(21

And we can find the probability with this difference

P(-1

And using the normal standard distribution or excel we got:

P(-1

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3 years ago
A college student is moving into a campus dormitory. The student rents a moving truck for $19.95 plus $.99 per mile. Before retu
tiny-mole [99]

Answer:

60 miles

Step-by-step explanation:

you have to do 19.95+ .99x+ 65.32= 144.67

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CAN YALL PLS HELP ASAPPP!!!!
Elena L [17]

Answer:

8/4 + 4/4

Step-by-step explanation:

Try it im not good at math :( but hope it helps :(:

3 0
2 years ago
If two lines intersect, what angles are congruent?
horrorfan [7]
Answer= Opposite Angles

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A particular variety of watermelon weighs on average 22.4 pounds with a standard deviation of 1.36 pounds. Consider the sample m
daser333 [38]

Answer:

a) 22.4 pounds.

b) 0.17 pounds.

c) 0.0127 = 1.27% approximate probability the sample mean weight will be less than 22.02.

d) c = 22.62

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Average 22.4 pounds with a standard deviation of 1.36 pounds.

This means that \mu = 22.4, \sigma = 1.36

Consider the sample mean weight of 64 watermelons of this variety.

This means that n = 64, s = \frac{1.36}{\sqrt{64}} = 0.17

a. What is the expected value of the sample mean weight?

By the Central Limit Theorem, 22.4 pounds.

b. What is the standard deviation of the sample mean weight?

By the Central Limit Theorem, 0.17 pounds.

c. What is the approximate probability the sample mean weight will be less than 22.02?

This is the p-value of Z when X = 22.02. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{22.02 - 22.4}{0.17}

Z = -2.235

Z = -2.235 has a p-value of 0.0127.

0.0127 = 1.27% approximate probability the sample mean weight will be less than 22.02.

d. What is the value c such that the approximate probability the sample mean will be less than c is 0.9?

This is the 90th percentile, that is, X = c when z has a p-value of 0.9, so X when Z = 1.28.

Z = \frac{X - \mu}{s}

1.28 = \frac{c - 22.4}{0.17}

c - 22.4 = 1.28*0.17

c = 22.62

4 0
3 years ago
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