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3 years ago

What’s the solution to x^2=18

Mathematics

2 answers:

Keith_Richards [23]3 years ago

6 0

The answer I think would be 9

shutvik [7]3 years ago

5 0

X= 3 times $\sqrt{2}$

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James is 5'10", Emily is 5'7", Ruby is 6'0", Chad is 6'0", Russell is 5'10", and Ariel is 5'9". What is the mean height of those

White raven [17]

Answer:

34'2" I think

Step-by-step explanation:

You just add them together and that was for the first part

5 0

3 years ago

4m - 9= 31<br><br> I can’t remember how to work this out. Can someone help?

lianna [129]

Answer:

Step-by-step explanation:

4m=40

m=10

5 0

3 years ago

Read 2 more answers

Given the following functions, evaluate each of the following:

Olegator [25]

Answer:

1. -6

Step-by-step explanation:

f(x)=x²-9

g(x)= x-3

1. (f+g)(2) =

(2²-9)+(2-3) = (4-9)+(2-3) = (-5)+(-1)= -6

8 0

2 years ago

Anyone know how to solve this??

Tom [10]

$Given : \frac{(x^\frac{2}{5})^9\;.\;(x^\frac{-4}{15})}{x^\frac{1}{3}}$

$\implies {(x^\frac{18}{5})\;.\; (x^\frac{-4}{15})}\;.\;(x^\frac{-1}{3})$

$\implies x^(^\frac{18}{5} ^-^\frac{4}{15}^-^\frac{1}{3}^)$

$\implies x^(^(^\frac{54 - 4}{15}^)^-^\frac{1}{3}^) = x^(^(^\frac{50}{15}^)^-^\frac{1}{3}^) = x^(^(^\frac{10}{3}^)^-^\frac{1}{3}^) = x^(^\frac{9}{3}^) = x^3$

$\implies x^k = x^3$

$\implies k = 3$

7 0

4 years ago

In a lab, a scientist is growing bacteria for a study. The scientist begins with a bacteria

Diano4ka-milaya [45]

Answer:

The answer is below

Step-by-step explanation:

The growth of the bacteria is in the form of an exponential growth. It is given by the formula:

$P(t)=ae^{rt}\\\\where\ t\ is\ the\ number\ of \ hours, P(t)\ is\ the \ population\ at\ t\ hours\\\and\ a=population\ at\ start$

At 2 hours, the population is 62 cells, hence:

$P(2)=ae^{2r}\\\\62=ae^{2r}\ \ .\ \ .\ \ .\ (1)$

After another 2 hours (4 hours), the population is 1 million:

$P(4)=ae^{4r}\\\\1000000=ae^{4r}\ \ .\ \ .\ \ .\ (2)\\\\Divide \ equation\ 2\ by\ equation\ 1:\\\\\frac{1000000}{62}=\frac{ae^{4r}}{ae^{2r}} \\\\16129=e^{2r}\\\\ln(e^{2r})=ln(16129)\\\\2r=9.688\\\\r=4.844$

Put r = 4.844 in equation 1

$62=ae^{2*4.844}\\\\62=16129a\\\\a=0.003844$

$P(t)=0.003844e^{4.844t}\\\\at \ start,t=0\\\\P(0)=0.003844$

4 0

3 years ago