The right matches are:
Ventricular fibrillation ==> Loss of consciousness and death
Two successive PVC's ==> Often asymptomatic
Bizarre ECG waves ==> Defibrillation is needed
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Ventricular fibrillation is a violent and disordered contraction of muscle fibers, especially the heart muscle, in the ventricles. This systematically leads to loss of consciousness or death.
Defibrillation is a treatment by electrical shock of abnormal contractions of the heart fibers, in order to restore a normal heart rhythm.
Premature contraction of the heart alters the normal heart rhythm but is clinically undetectable or expressed as palpitations.
Answer:
raspberry jam - benedict's solution
honey - benedict's solution
ground turkey - biuret reagent
oatmeal - iodine
Explanation:
Benedict's test is a test used to confirm simple carbohydrates. it helps in identifying reducing sugars that have free ketone or aldehyde functional groups. Raspberry jam has mainly carbohydrates that can be tested by this indicator.
An iodine test is for the determination of starch which is a non-reducing sugar such as oatmeal
Sudan IV (C24H20N4O) is used for the presence of staining of lipids, triglycerides and lipoproteins. There is no food item given that has a proper amount of fat or lipid
Beuret reagent is a protein testing reagent that shows the presence of the protein. Ground turkey has a huge amount of protein that can be indicated by this
Answer: The skeletal portion of the system serves as the main storage is to help regulate mineral balance in the bloodstream.
I hope this help. Stay safe, wash your hands
Answer: Hello your question is incomplete below is the complete question
Let’s look at a different gene locus, we’ll call it B. The normal, wild type, the population was 100% BB. There are 150 Pakicetus in the population at present. Assume Charles had another mutation; this one at the B locus, to produce allele b. What is the gene frequency of allele b in the population if the population of Pakicetus reaches 100,000
answer : ≈ 1
Explanation:
<u>Determine the Gene frequency of allele b </u>
Population = 100,000
There are 150 Pakicetus in population i.e. 300 alleles at locus B
hence the frequency of b = 1/300 = 0.33%
Increase in population does not affect frequency of b ( HW equilibrium )
<em>therefore the Gene frequency of allele b </em>
= 0.33% * 0.33% * 100000 = 1.08
≈ 1
Answer:
2 in 4
Explanation:
If a female cat with orange fur (XOXO) is crossed with a male cat with black fur (XoY) then:
P: XOXO x XoY
F1: XOXo XOY XOXo XOY
This means that half of the offspring will be females with tortoiseshell color (XOXo) and other half of the offspring will be males with orange fur (XOY).