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3 years ago

Which equation represents a line that is parallel to the x-axis, is perpendicular to the y-axis, and has a slope of 0?

Mathematics

1 answer:

Katarina [22]3 years ago

6 0

Answer:

Step-by-step explanation:

c does not have a slope so the slope is 0 and it is parallel to the x axis bc the line will be vertical on a graph making it perpendicular on the y axis

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Trains Two trains, Train A and Train B. weigh a total of 196 tons. Train A is heavier than Train B. The

aleksklad [387]

Answer:

Train A = 128

Train B = 68

Step-by-step explanation:

We can set up a system of equations for this problem

Let A = # of tons of Train A

Let B = # of tons of Train B

A + B = 196

A = B + 60

Now, we plug in A for the first equation, using substitution

(B+60) + B = 196

2B + 60 = 196

Subtract 60 from both sides

2B = 136

Divide both sides by 2

B = 68

Plug in 68 for B in the 2nd equation

A = 68 + 60

A = 128

Checking work: 128 + 68 = 196 :D hope this helped

5 0

2 years ago

Len's recipe for blueberry muffins calls for 110.25 g of brown sugar for the muffin batter and an additional 55.45 g of brown su

nasty-shy [4]

This may be wrong but this is how id do it.

110.25 + 55.45 = 165.7

165.7 x 4.5 = 745.65 g of brown sugar

6 0

3 years ago

If y = 2 and x = 5, Then solve 3x + 4 + 2y A 20 B 61 C 23 D 0

Arisa [49]

Answer:

Step-by-step explanation:

8 0

3 years ago

If you get $2,000 for graduation gifts and invest it in an account that earns 1.5% interest

Eduardwww [97]

Answer:

It is VERY important to use the attached formula.

Years = ln (Total / Principal) / rate

Years = ln (6,000 / 2,000) / rate

Years = ln (3) / rate

Years = 1.0986122887 / .015

Years = 73.24 years

This takes a LONG time because the interest rate is extremely low.

Step-by-step explanation:

5 0

3 years ago

Which expression is equivalent to 4^ 5x4^ -7÷4 ^-2?

Andre45 [30]

$\bf ~~~~~~~~~~~~\textit{negative exponents} \\\\ a^{-n} \implies \cfrac{1}{a^n} \qquad \qquad \cfrac{1}{a^n}\implies a^{-n} \qquad \qquad a^n\implies \cfrac{1}{a^{-n}}\\\\[-0.35em] \rule{34em}{0.25pt}\\\\ 4^5\cdot 4^{-7}\div 4^{-2}\implies \cfrac{4^5\cdot 4^{-7}}{4^{-2}}\implies \cfrac{4^{5-7}}{4^{-2}}\implies \cfrac{4^{-2}}{4^{-2}}\implies 4^{-2}\cdot 4^2 \\\\\\ 4^{-2+2}\implies \boxed{4^0}\implies 1$

5 0

3 years ago

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