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Mazyrski [523]
4 years ago
7

Another question this math is not my favorite ? Struggling but son what understanding it . Help please

Mathematics
1 answer:
Evgen [1.6K]4 years ago
5 0
12/3= 4 <-- This equation shows that one box will benefit 4 children.
24/4=6 <-- This equation shows how many boxes will benefit 24 children.

Therefore, Raymond should buy 6 boxes.
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It takes mario 5 minutes to type 225 words.how many many minutes does it take him to type 360 words?enter your answer in the box
elena-s [515]
225/5 = 360/x

225x = 1,800

225x/225 = 1,800/225 = 8

It would take him 8 minutes
8 0
3 years ago
Read 2 more answers
The number y of hits a new website receives each month can be modeled by y = 4070ekt, where t represents the number of months th
makvit [3.9K]

Answer:

<u><em>k = 0.2645</em></u>

Step-by-step explanation:

Given model:

y = 4070 e^{kt}

y = no. of hits website received = 9000 (in 3rd month)

t= no. of months website has been operational = 3

put in the above equation:

9000 = 4070  e^{3k}

\frac{9000}{4070} = e^{3k}

\frac{900}{407}=e^{3k}

<u><em>Taking natural logarithm on both sides, we get:</em></u>

ln\frac{900}{407}=ln(e^{3k})

ln\frac{900}{407}= 3k ln<em>e</em>

ln<em>e</em>=1

ln \frac{900}{407}= 3k

or k = \frac{1}{3}ln\frac{900}{(407)}

k =\frac{1}{3}(0.7936)

<em>k = 0.2645</em>

<em />

7 0
3 years ago
The diameter of a cylindrical construction pipe is 4ft If the pipe is 17ft long, what is its volume? Use the value 3.14 for /pi,
zvonat [6]

Answer:

214 ft^3

Step-by-step explanation:

Here, we are asked to calculate the volume of the cylindrical construction pipe.

Mathematically, the volume V

V = pi * r^2 * h

r is radius = diameter/2 = 4/2 = 2 ft

h = 17ft

pi = 3.14

Putting these values, we have;

V = 3.14 * 2^2 * 17 = 213.52 which is 214 ft^3 to the nearest whole number

8 0
3 years ago
Whats is the square root of 2 multiply by one over the square root of 2
Ket [755]

When ANY number is multiplied by its own reciprocal, the product is ' 1 '.

8 0
4 years ago
What is the graph of f(x)= 2x^2
konstantin123 [22]
Since this is a fairly small equation, it's pretty easy to plug in a few points to get ordered pairs and sketch a graph:

when x = 0...
f(0) = 2(0)^2
f(0) = 0
(0, 0)

when x = 1...
f(1) = 2(1)^2
f(1) = 2
(1, 2)

when x = -1...
f(-1) = 2(-1)^2
f(-1) = 2
(-1, 2)

from there, you can get a rough sketch of the graph just by plotting those points. essentially, it just looks "skinnier" than your typical parabola because the 2 out front makes the curve steeper.
3 0
3 years ago
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