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julia-pushkina [17]
2 years ago
8

If The area of a triangle is 84 square meters. What is the base if the height is 12 meters?

Mathematics
2 answers:
Delicious77 [7]2 years ago
5 0

Answer:

14

Step-by-step explanation:

Softa [21]2 years ago
3 0
14 is correct I’m pretty sure
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Find x, round to the nearest tenth.
Paladinen [302]

Answer:

Step-by-step explanation:

Law of Cosines

x = √(40²+12² - 2·40·12·cos(37°)) ≅ 31.3 units

7 0
3 years ago
2.5 +1 <br><img src="https://tex.z-dn.net/?f=2.5%20%2B%201%20%5Cfrac%7B1%7D%7B2%7D%20" id="TexFormula1" title="2.5 + 1 \frac{1}{
OverLord2011 [107]

Answer:

4

Step-by-step explanation:

2.5+1 1/2

Change the fraction to a decimal

2.5 + 1.5

4

6 0
3 years ago
I need help with this ​
harkovskaia [24]
1. x=24

2. r=9

3. w=33

4. n=19
6 0
2 years ago
A study reported that the average age of menarche of girls entering the first year class of a small American private college in
Verizon [17]

Answer:

Null hypothesis: \mu = 11.89

Alternative hypothesis: \mu \neq 11.89

And we want to test this with a confidence interval:

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

After conduct the interval of 95% for the true mean we got: (11.59, 13.31)

And for this case the confidence interval contains the value of 11.89, so then we have enough evidence to FAIL to reject the null hypothesis at 5% of significance that the true mean is 11.89.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=12.98 represent the sample mean for the sample  

\mu population mean (variable of interest)

s represent the sample standard deviation

n=30 represent the sample size  

Solution to the problem

For this case we want to test the following hypothesis:

Null hypothesis: \mu = 11.89

Alternative hypothesis: \mu \neq 11.89

And we want to test this with a confidence interval:

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

After conduct the interval of 95% for the true mean we got: (11.59, 13.31)

And for this case the confidence interval contains the value of 11.89, so then we have enough evidence to FAIL to reject the null hypothesis at 5% of significance that the true mean is 11.89.

4 0
3 years ago
Solve the equation x = -2y + 6 for y
klio [65]

Answer:

x=2y=6

Step-by-step explanation:

x+2y=-2y+6+2y

5 0
3 years ago
Read 2 more answers
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