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miskamm [114]
4 years ago
6

Jessica has some round stickers. Each sticker has a radius of 2 cm. She is trying to cover as much of a sheet of paper that is 2

4 cm by 33 cm as possible without any overlap and modification of the stickers. How much of the bare paper will be visible around the stickers?
Mathematics
1 answer:
nata0808 [166]4 years ago
8 0

Answer:

189.12 cm²

Step-by-step explanation:

If the radius of the stickers is 2 cm, then the diameter of each sticker is 4 cm.

1. Using this, divide each length of the sheet of paper by the diameter of 4 cm to see how many stickers can fit without overlapping.

24 ÷ 4 = 6 stickers

33 ÷ 4 = 8.25 = 8 stickers (only eight whole stickers will fit without overlap)

This means there can be a total of 48 stickers because 6*8 = 48.

2. Find the area of one sticker. The formula for the area of a circle if πr² (pi times radius squared) with 3.14 equal to π.

3.14 · 2² → 3.14 · 4 = 12.56 cm²

3. Multiply the area by the number of stickers that can fit on the sheet of paper (48 stickers).

12.56 · 48 = 602.88 cm²

4. Find the area of the sheet of paper. The formula for the area of a rectangle is length · width.

24 · 33 = 792 cm²

5. Subtract the area of the stickers from the area of the sheet of paper to solve for the remaining bare paper around the stickers.

792 - 602.88 = 189.12 cm²

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