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Feliz [49]
3 years ago
11

In a far-off land three fish can be traded for two loaves of bread and a loaf of bread can be traded for four bags of rice. How

many bags of rice is one fish worth?
Mathematics
1 answer:
timofeeve [1]3 years ago
3 0
2.5 bags of rice are worth one fish
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Points A, B, and C are collinear. Point B is between A and C. AB = 10 and BC = 5. Find AC.
malfutka [58]

Answer:

AC = 15

Step-by-step explanation:

Use segment addition postulate to add AB + BC = AC. 10 + 5 = 15.

(drawing out the line helps you visualize the problem better)

5 0
4 years ago
Read 2 more answers
4 1/5 ÷ 2/3 this is a
wel

Answer:

27/4 also written as 6.75 and 6 3/4


7 0
3 years ago
HELP???? PLEASE AND FAST IM ON THE BRINK OF DEATH --
aleksandrvk [35]

Answer:

See below.

Step-by-step explanation:

Create a system of equations to represent this scenario.

  • Lin: 12 - 1/3x = y
  • Diego: 20 - 2/3x = y  

1) A graph of these equations is attached below. Lin is in red; Diego is in blue.

2) The time (seconds) is on the x-axis, while the milkshake (oz) is on the y-axis. The graph shows the rate of change that the volume of the milkshake is decreasing for both Lin and Diego. The intersection point tells us at what time t (s) Lin and Diego have the same amount of milkshake left.

There is only one solution to this system of equations: (24, 4). This tells us that at t = 24 s, Lin and Diego both have 4 oz of milkshake left.

The zeros, aka where the graph touches the x-axis, tell us at what time Lin and Diego finish their milkshakes.

Lin finishes her milkshake later than Diego, at t = 36 s (36, 0), while Diego finishes his milkshake at t = 30 s (30, 0).

3 0
3 years ago
Over the summer, for every 13 okra seeds Dana planted, 8 grew into plants. If he planted 130 okra seeds, how many grew into plan
schepotkina [342]
The answer will be 26 beaus if you subtract 13 by 8 that equals 5 and if u divide that number by 130 it will equal 26
6 0
3 years ago
A quality-conscious disk manufacturer wishes to know the fraction of disks his company makes which are defective. Step 2 of 2: S
Anna35 [415]

Answer:

The 98% confidence interval for the population proportion of disks which are defective is (0.082, 0.118).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

Suppose a sample of 1536 floppy disks is drawn. Of these disks, 1383 were not defective.

1536 - 1383 = 153

This means that n = 1536, \pi = \frac{153}{1536} = 0.1

98% confidence level

So \alpha = 0.02, z is the value of Z that has a pvalue of 1 - \frac{0.02}{2} = 0.99, so Z = 2.327.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.1 - 2.327\sqrt{\frac{0.1*0.9}{1536}} = 0.082

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.1 + 2.327\sqrt{\frac{0.1*0.9}{1536}} = 0.118

The 98% confidence interval for the population proportion of disks which are defective is (0.082, 0.118).

6 0
3 years ago
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