Answer:
Range is {y | y ≥ –11}
Step-by-step explanation:
This is quadratic equation.
<em>A quadratic equation's range can be found if we find the vertex.</em>
For quadratic equations that have a positive number in front of
, it is upward opening and thus <u>all the numbers greater than or equal to the minimum value of vertex is the range.</u>
The formula for vertex of a parabola is:
Vertex = ![(-\frac{b}{2a}, f(-\frac{b}{2a})](https://tex.z-dn.net/?f=%28-%5Cfrac%7Bb%7D%7B2a%7D%2C%20f%28-%5Cfrac%7Bb%7D%7B2a%7D%29)
Where,
is the coefficient of ![x^{2}](https://tex.z-dn.net/?f=x%5E%7B2%7D)
is the coefficient of ![x](https://tex.z-dn.net/?f=x)
From our equation given,
and ![b=6](https://tex.z-dn.net/?f=b%3D6)
Now,
coordinate of vertex is ![x=-\frac{b}{2a}\\x=-\frac{6}{(2)(3)}\\x=-\frac{6}{6}\\x=-1](https://tex.z-dn.net/?f=x%3D-%5Cfrac%7Bb%7D%7B2a%7D%5C%5Cx%3D-%5Cfrac%7B6%7D%7B%282%29%283%29%7D%5C%5Cx%3D-%5Cfrac%7B6%7D%7B6%7D%5C%5Cx%3D-1)
coordinate of the vertex IS THE MINIMUM VALUE that we want. We get this by plugging in the
value [
] into the equation. So we have:
![3(-1)^{2}+6(-1)-8\\=-11](https://tex.z-dn.net/?f=3%28-1%29%5E%7B2%7D%2B6%28-1%29-8%5C%5C%3D-11)
Hence, the range would be all numbers greater than or equal to
Third answer choice is the right one.
Answer:
Length of IK is 8 feet, EK is 11 feet and BE is 25 feet.
Step-by-step explanation:
It is given that radius for circle B is 6 feet, circle K is 14 feet and circle D is 3 feet. In order to find the length, you have to either substract or add up :
IK = BK(radius of K) - BI(radius of B)
= 14 - 6
= 8 feet
EK = DK(radius of K) - DE(radius of D)
= 14 - 3
= 11 feet
BE = BK + EK(answer above)
= 14 + 11
= 25 feet
Multiplying 60 x 20 = 1,200