Answer:
A. 
B. 
C. 
D. 
Explanation:
Hello.
In this case, we must compute the final concentration in all the cases so we solve for it in the given equation:
Thus, we proceed as follows:
A. Here, the final diluted solution includes the 300 μL of the 5 mg/ml-BSA and the 700 μL of TBS.
B. Here, the final diluted solution includes the 50 μL of the 1.5 mg/ml-BSA, the 450 μL of water and the 500 μL of TBS.
C. Here, the final diluted solution includes the 10 μL of the 1 mg/ml-BSA and the 990 μL of TBS.
D. Here, the final diluted solution includes the 10 μL of the 0.1 mg/ml-BSA and the 990 μL of TBS.
Best regards.
Answer: Option D) 1:4
Explanation:
Recall that the sum of all nitrogenous bases in the DNA nucleotide is equal to 100%. And specific base pairings of Adenine to Thymine (A=T), and Cytosine to Guanine (C=G) must be equal.
So, the percentage of Adenine equal thymine, and that of cytosine equals guanine.
Now, A + T + C + G = 100%
So, if adenine makes up 10% of the DNA nucleotides, then thymine is also 10%.
Then, 10% + 10% + C + G = 100%
20% + C + G = 100%
C + G = 100% - 20% = 80%
Thus, divide 80% by 2 to obtain the individual percentage of cytosine and guanine. Each will take 40%
Ratio Adenine to Guanine is 10% to 40%
or 1:4 in simplest form
Plants use rigid cell playes to divide
I am so positive it’s D because that’s the only one that makes sense. Trust me
