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Savatey [412]
3 years ago
12

How do you solve Walt grew 10 centimeters in 1 year he is now 1.6 m tall how tall was he 1 year ago

Mathematics
1 answer:
tresset_1 [31]3 years ago
5 0
If he grew 10 cm in 1 yr.....he would be 10 cm less then he is now.

1 m = 100 cm......so 1.6 m = (1.6 x 100) = 160 cm.

so he is 160 cm now......and 1 yr ago, he would be (160 - 10) = 150 cm....or 1.5 m.
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By the quadratic formula,

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Then

(x^2+1)^2=\dfrac{25\pm10\sqrt5+5}4=\dfrac{15\pm5\sqrt5}2

\implies\dfrac{x^2}{(x^2+1)^2}=\dfrac{\frac{3\pm\sqrt5}2}{\frac{15\pm5\sqrt5}2}=\dfrac{3\pm\sqrt5}{15\pm5\sqrt5}

Multiply numerator and denominator by the denominator's conjugate:

\dfrac{3\pm\sqrt5}{15\pm5\sqrt5}\cdot\dfrac{15\mp5\sqrt5}{15\mp5\sqrt5}=\dfrac{45\pm15\sqrt5\mp15\sqrt5-25}{15^2-(5\sqrt5)^2}=\dfrac{20}{100}=\dfrac15

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