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Savatey [412]
3 years ago
12

How do you solve Walt grew 10 centimeters in 1 year he is now 1.6 m tall how tall was he 1 year ago

Mathematics
1 answer:
tresset_1 [31]3 years ago
5 0
If he grew 10 cm in 1 yr.....he would be 10 cm less then he is now.

1 m = 100 cm......so 1.6 m = (1.6 x 100) = 160 cm.

so he is 160 cm now......and 1 yr ago, he would be (160 - 10) = 150 cm....or 1.5 m.
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What is the solution to the equation x + 7.5 = 21.5? A.x = 2.9 B.x = 7.8 C.x = 14 D.x = 29
dedylja [7]
X+7.5=21.5
Subtract 7.5 from both sides
X=14 which is C
hope this helps good luck have a nice day
8 0
3 years ago
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I need help with math here the photos
arsen [322]

Answer:

9-49

a=  2r+ 7

b= 2.5x + 16

c= 3r-2x-8.8

Step-by-step explanation:

4 0
2 years ago
A variety of two types of snack packs are delivered to a store. The box plots compare the number of calories in each snack pack
adelina 88 [10]

OPTIONS:

A. The interquartile range of the trail mix data is greater than the range of the cracker data.

B. The value 70 is an outlier in the trail mix data.

C. The upper quartile of the trail mix data is equal to the maximum value of the cracker data.

D. The number of calories in the packs of trail mix have a greater variation than the number of calories in the packs of crackers.

Answer:

D.

Step-by-step explanation:

With the given information about how the box plot looks like, let's examine each option to see if they are true or not.

<u><em>Option A: "The interquartile range of the trail mix data is greater than the range of the cracker data."</em></u>

The interquartile range of trail mix data = 105 - 90 = 15

Range of cracker data = 100 - 70 = 30

Option A is NOT TRUE.

<u><em>Option B: "The value 70 is an outlier in the trail mix data.</em></u>"

This is NOT TRUE. There are not outliers as 70 is the minimum value if the ranges of the data set for the trail mix.

<em><u>Option C: "The upper quartile of the trail mix data is equal to the maximum value of the cracker data."</u></em>

Upper quartile of the trail mix data = 105

Max value of cracker data = 100

This statement is NOT TRUE.

<em><u>Option D: "The number of calories in the packs of trail mix have a greater variation than the number of calories in the packs of crackers."</u></em>

The greater the range value, the greater the variation. Thus,

Range value of the trail mix data = 115 - 70 = 45

Range value of the cracker data = 100 - 70 = 30

This is statement is correct because trail mix data have a greater range value, hence, it has a greater variation in the number of calories.

6 0
3 years ago
Read 2 more answers
PLEASE HELP ME WITH IT.
scoundrel [369]

OK.  I did it.  Now let's see if I can go through it without
getting too complicated.

I think the key to the whole thing is this fact:

     A radius drawn perpendicular to a chord bisects the chord.

That tells us several things:

-- OM bisects AB. 
   'M' is the midpoint of AB.
   AM is half of AB.

-- ON bisects AC.
    'N' is the midpoint of AC.
   AN is half of AC.

--  Since AC is half of AB,
     AN is half of AM.
     a = b/2 

Now look at the right triangle inside the rectangle.
'r' is the hypotenuse, so

                                            a² + b² = r²

But  a = b/2, so             (b/2)² + b² = r²

(b/2)² = b²/4                   b²/4   + b² = r²

Multiply each side by 4:     b² + 4b² = 4r²
                                       -  -  -  -  -  -  -  -  -  -  -
                                            0  + 5b² = 4r²  
Repeat the
original equation:                a² +  b² =  r²

Subtract the last
two equations:                  -a² + 4b² = 3r² 

Add  a²  to each side:              4b²  =  a² + 3r² .    <=== ! ! !
 
7 0
3 years ago
Please help if you can!
Serhud [2]

Answer:

-3

Step-by-step explanation:

that’s where the line intercepts with the y axis

4 0
2 years ago
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