3 years ago

Im wasting my points pls answer

Mathematics

1 answer:

scoundrel [369]3 years ago

8 0

Answer:

1 1/15

1 7/15

I think that the sister rode farther by 2/5

reason:

(the sister) 2/3 mile+4/5 mile=1 7/15

(you) 2/3 mile+2/5=1 1/15

1 7/15-1 1/15= 2/5(according to a website I used)

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Reil [10]

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3 years ago

Sketch the region enclosed by the given curves. Decide whether to integrate with respect to x or y. Draw a typical approximating

MakcuM [25]

Answer:

A=8.4063 $u^{2}$

Step-by-step explanation:

Be the functions:

$y=\frac{3}{x};y=\frac{3}{x^{2}}:x=7$

according the graph:

$\int\limits^1_7 {\frac{3}{x} } \, dx -\int\limits^1_7 {\frac{3}{x^{2} } } \, dx =3\int\limits^1_7 {\frac{1}{x} } \, dx -3\int\limits^1_7 {\frac{1}{x^{2} } } \, dx=3(\int\limits^1_7 {\frac{1}{x} } \, dx -\int\limits^1_7 {\frac{1}{x^{2} } } \, dx)=3[lnx-\frac{1}{x}](1-7)=3[(ln7-ln1)-(\frac{1}{7}-1)]=3[(1.945-0)-(0.1428-1)]=3*(1.945+0.8571)=3*2.8021=8.4063u^{2}$