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Jobisdone [24]
3 years ago
15

the cube below is divided into 8 equal cubes and broken apart. what is the total surface area of all 8 cubes

Mathematics
1 answer:
skelet666 [1.2K]3 years ago
8 0
The area of a cube is A= 6L^2.  A=surface area, L= edge length

The total area is 6(2L^2)  ---> 12L^2. Because when we place the 8 cubes (use 4 cubes to make a square then stack another 4 cube square) to form the original, the small cube's edge (length) is doubled.


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The width of a rectangle is 7t - 1.5 feet and the length is 1.5t + 5 feet. Find the perimeter of the
mezya [45]

Answer:

P = 17t + 7

Step-by-step explanation:

P = 2L + 2w

L = 1.5t + 5

w = 7t - 1.5

P = 2*(1.5t  + 5) + 2*(7t - 1.5)

P = 3t + 10 + 14t - 3

P = 17t + 7

4 0
3 years ago
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Murljashka [212]
Massage me if it’s not clear

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A line passes through the point (0, 5) and has a slope of -5/4 what is the equation of the line?
TiliK225 [7]

Answer:

y=-5/4x+5

Step-by-step explanation:

( 0 , 5 )

The 5 is the y point meaning.

y = -5/4 x + 5

*slope

y = -5/4 x + 5

*where it crosses the y-axis

5 0
3 years ago
The task I need explaining is: how to show that an estimate of the mean time spent on homework is 64.8 minutes. Thanks!
xenn [34]
It's just an estimate.  There's no telling how close it is.

To estimate using just the information in the table,
ASSUME that the average of all the students in each
slot is the average time of that slot.

I know that's confusing.  I can't think of a better way to say it,
so here are two examples of what I mean.  Look at the table:

-- 6 students said that they spent between 0 and 30 minutes.
   ASSUME that those 6 students averaged 15 minutes each.

-- 21 students said that they spent between 60 and 90 minutes.
   ASSUME that those 21 students averaged 75 minutes each.

So, when you add up the times for all 50 students, you'll have

 (6 x 15 min) + (14 x 45 min) + (21 x 75min) + (9 x 105 min) =

When you total up all those times, divide it by 50 to estimate
the average per student.  

Remember ... it's only an estimate.
If the first group had 1 student that spent 2 minutes, and
the other 5 of them spent 29 minutes, then it won't work.
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5 0
3 years ago
What is the area where if this figurine ?ixl question
nydimaria [60]

Answer:

The area of the figure is 97 square inches

Step-by-step explanation:

In the given figure

<em>To find the area of the figure we can find </em><em>the area of the big rectangle with dimensions 7 inches and 19 inches</em><em> and subtract from it </em><em>the area of the small rectangle with dimensions 4 inches and 9 inches</em>

∵ The area o the rectangle = length × width

∵ The dimensions of the big rectangle are 7 inches and 19 inches

∴ The width = 7 inches

∴ The length = 19 inches

→ Substitute them in the rule of the area above

∵ The area of the big rectangle = 19 × 7

∴ The area of the big rectangle = 133 inches²

∵ The dimensions of the small rectangle are 4 inches and 9 inches

∴ The width = 4 inches

∴ The length = 9 inches

→ Substitute them in the rule of the area above

∵ The area of the small rectangle = 9 × 4

∴ The area of the small rectangle = 36 inches²

→ Subtract the area of the small rectangle from the area of the big

   rectangle to get the area of the green figure

∵ The area of the figure = the big area - the small area

∴ The area of the figure = 133 - 36

∴ The area of the figure = 97 inches²

∴ The area of the figure is 97 square inches

6 0
3 years ago
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