Answer:
Perimeter of rectangle = 6√10 units (the attachment isnt clear. It seems the answer is in option B)
Step-by-step explanation:
First we find the distance of the length and width of the rectangle.
Distance between E and F = Distance EF
Distance EF = √(∆y²-∆x²)
= √[(5-7)² + (1-7)²] = √[(-2)² + (-6)²]
= √(4+36) = √40
Distance EF = 2√10
Distance between F and G = Distance FG
Distance FG = √(∆y²-∆x²)
= √[(2-5)² + (2-1)²] = √[(-3)² + (1)²]
= √(9+1) = √10
Distance FG = √10
Length= distance EF = distance HG
And width = distance FG = distance EH
Perimeter of rectangle = 2(length + width)
Perimeter of rectangle = 2(2√10 + √10)
= 2(3√10)
Perimeter of rectangle = 6√10 units (the attachment isnt clear. It seems the answer is in option B)
The answer is 6y^3+17y^2+22y+15
Answer:
I think A=66.67?Not too sure,sorry if I am wrong
Step-by-step explanation:
X+82
...............::::;:
