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3 years ago

13

What is 3.5 rounded to the nearest hundredth? HELP QUICK

2 answers:

andrew-mc [135]3 years ago

7 0

If u round 3.5 to the nearest hundredth it would be 4.0

PSYCHO15rus [73]3 years ago

5 0

4.0!

3.5=350
thats is 4.0

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3 years ago

Match the y-coordinate with the given x-coordinate for the equation y = log10x.

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The non-algebraic functions are called transcendental functions. This include the logarithmic function. The definition of Logarithmic Function with Base a is as follows:

$For \ x\ \textgreater \ 0, \ a \ \textgreater \ 0, \ and \ a \neq 1 \\ \\ y=log_{a}x \ if \ and \ only \ if \ x=a^{y} \\ \\ Then: \\ \\ f(x)=log_{a}x \\ \\ is \ called \ the \ logarithmic \ function \ with \ base \ a.$

We know that the equations is:

$y=log(10x)$

So let's solve each case:

Case 1

$x=\frac{1}{100} \\ \\ y=log(10(\frac{1}{100})) \\ \\ \therefore y=log(\frac{1}{10}) \\ \\ \therefore y=-1 \\ \\ So: \\ \\ \boxed{\ x=\frac{1}{100}} \ matches \ to \ \boxed{y=-1}$

Case 2

$x=\frac{1}{10} \\ \\ y=log(10(\frac{1}{10})) \\ \\ \therefore y=log(1) \\ \\ \therefore y=0 \\ \\ So: \\ \\ \boxed{\ x=\frac{1}{10}} \ matches \ to \ \boxed{y=0}$

Case 3

$x=1 \\ \\ y=log(10(1)) \\ \\ \therefore y=log(10) \\ \\ \therefore y=1 \\ \\ So: \\ \\ \boxed{\ x=1} \ matches \ to \ \boxed{y=1}$

Case 4

$x=10 \\ \\ y=log(10(10)) \\ \\ \therefore y=log(100) \\ \\ \therefore y=2 \\ \\ So: \\ \\ \boxed{\ x=10} \ matches \ to \ \boxed{y=2}$

Case 5

$x=100 \\ \\ y=log(10(100)) \\ \\ \therefore y=log(1000) \\ \\ \therefore y=3 \\ \\ So: \\ \\ \boxed{x=100} \ matches \ to \ \boxed{y=3}$

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4 years ago

Read 2 more answers

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an integer between –11 and –10

a whole number between 1 and 2

a terminating decimal between –3.14 and –3.15

Step-by-step explanation:

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2 years ago

with H1:p>0.75 a test statistic is z=0.55. use a 0.05 significance level to find th p value and state the conclusion about th

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3 years ago

Sam has a jar contain 80 coins, all of which are either quarters or nickels. The total value of the coins is $14.60. How many of

DENIUS [597]

Answer:

She have <u>53</u> type of quarters and <u>27</u> type of nickels.

Step-by-step explanation:

Given:

Sam has a jar contain 80 coins, all of which are either quarters or nickels.

The total value of quarters and nickels is $14.60.

Now, to get each type of coin she have.

Let the number of quarters be $x.$

And let the number of nickels be $y.$

<u><em>So, total number of coins:</em></u>

$x+y=80$

$y=80-x\ \ \ ....(1)$

<u><em>Now, the total value of coins:</em></u>

$0.25(x)+0.05(y)=14.60$

Substituting the value of $y$ from equation (1):

$0.25(x)+0.05(80-x)=14.60$

$0.25x+4-0.05x=14.60$

$0.20x+4=14.60$

<em>Subtracting both sides by 4 we get:</em>

<em /> $0.20x=10.60$ <em />

<em>Dividing both sides by 0.20 we get:</em>

$x=53.$

<u>The number of quarters = 53.</u>

Now, to get the number of nickels by substituting the value of $x$ in equation (1):

$y=80-x\\\\y=80-53\\\\y=27.$

<u>The number of nickels = 27.</u>

Therefore, she have 53 type of quarters and 27 type of nickels.

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3 years ago