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2 years ago

Find 39% of 65 show work plz

Mathematics

2 answers:

Papessa [141]2 years ago

7 0

The answer is 25.35.

In mixed fraction form its 25 7/20.

All u have to do is multiply 65 * 39% and u get 25.35.

sukhopar [10]2 years ago

7 0

65/x=100/39
(65/x)*x=(100/39)*x - we multiply both sides of the equation by x
65=2.5641025641*x - we divide both sides of the equation by (2.5641025641) to get x
65/2.5641025641=x
25.35=x
x=25.35

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What’s the answer to this?

inna [77]

Since the triangle is equilateral, all its angles are equal to 60°

AO is the bisector⇒∠OAD = 30°

AO is the hypotenuse, ∠OAD = 30°⇒

OD=5*2=10m

By the Pythagorean theorem

$10^2=AD^2+5^2\\AD=\sqrt{100-25} \\AD=\sqrt{75}$

$AC=AD+DC=2\sqrt{75}=10\sqrt{3}$

$S=\frac{a^2\sqrt{3} }{4}$

$S=\frac{(10\sqrt{3})^2\sqrt{3} }{4} =\frac{300\sqrt{3} }{4} =75\sqrt{3} m^2$

Answer: A) $S=75\sqrt{3}$ m²

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3 0

2 years ago

Find the value of x, y, and z in the rhombus below.

34kurt

Answer:

Step-by-step explanation:

For a rhombus, the opposite angles are equal:

74=5y+9

5y=65

y=13

For a rhombus, the adjacent angles are supplementary:

74+(z-10)=180

z-10=106

z=116

74+(x+7)=180

x+7=106

x=99

3 0

2 years ago

Read 2 more answers

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cricket20 [7]

$\qquad\qquad\huge\underline{{\sf Answer}}$

Here's the solution :

9. Statement : $\tt{VB\:\: bisects\;\; \angle EVO}$

Reason : $\tt Given$

10. Statement : $\tt \angle3 \cong \angle 4$

Reason : $\tt Definition \;\; of \;\; angle \;\; bisector$

11. Statement $\tt{VB\:\: bisects\;\; \angle EBO}$

Reason : $\tt Given$

12. Statement : $\tt \angle1 \cong \angle 2$

Reason : $\tt Definition \;\; of \;\; angle \;\; bisector$

13. Statement : $\tt \overline{BV }\cong \overline{BV}$

Reason : $\tt Common\:\: side$

14. Statement : $\tt \triangle \:BEV \cong \triangle \:BOV$

Reason : $\tt ASA \:\: postulate$

15. Statement : $\tt \angle E \cong \angle O$

Reason : $\tt Corresponding\;\;parts\:\: of\:\: Congruent \;\;Triangles$

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2 years ago

Name the sets of numbers to which -10 belongs

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3 years ago

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2 years ago