Answer:
<h2>For the first triangle, <u>x equals 22cm.</u></h2>
Here's how:-
x is the altitude or height of the triangle. To find it, we can use the Pythagoras theorem:-
The base is 120cm and the hypotenuse is 122cm
Putting this in the equation, we get:-
= 484
altitude = 
<h3>altitude = 22cm</h3><h2><u>So, x = 22cm</u></h2>
Answer:
Yes
Step-by-step explanation:
4 x 3 = 12
5 x 3 = 15
Answer:
WZ = 30
Step-by-step explanation:
set up equation based on WZ = W'Z'
3/4[6x + 10] = 13x - 35
multiply each side of equation by 4 to eliminate fractions:
18x + 30 = 52x - 140
-34x = -170
x = 5
substitute 5 for 'x' in either expression:
13(5) - 35
65 - 35 = 30
The equation of the parabolas given will be found as follows:
a] general form of the parabolas is:
y=k(ax^2+bx+c)
taking to points form the first graph say (2,-2) (3,2), thus
y=k(x-2)(x-3)
y=k(x^2-5x+6)
taking another point (-1,5)
5=k((-1)^2-5(-1)+6)
5=k(1+5+6)
5=12k
k=5/12
thus the equation will be:
y=5/12(x^2-5x+6)
b] Using the vertex form of the quadratic equations:
y=a(x-h)^2+k
where (h,k) is the vertex
from the graph, the vertex is hence: (-2,1)
thus the equation will be:
y=a(x+2)^2+1
taking the point say (0,3) and solving for a
3=a(0+2)^2+1
3=4a+1
a=1/2
hence the equation will be:
y=1/2(x+2)^2+1
