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Lunna [17]
3 years ago
11

What does (2m + 7) - (3 - 4m) equal

Mathematics
1 answer:
yaroslaw [1]3 years ago
5 0
(2m + 7) - (3 - 4m) = 2m + 7 - 3 + 4m = (2m + 4m) + (7 - 3)

= <u>6m + 4</u>
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S=194, L=75 L+S=269, 4L+1S=$494

Step-by-step explanation:

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Mr.smith and mr.Stein We’re driving to a business meeting 100 miles from their office. Mr.smith Drove the first y miles ,then mr
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mrs smith drove 50 miles and mr stein drove 50 mile

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3 years ago
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Please help :) I’m really in need of assistance and would appreciate it.
BaLLatris [955]

Answer:

D) 0.5x^3y + 4x^2 y^2 - 2xy^3

Step-by-step explanation:

Set up an equation to model the situation,

(-0.5xy)(x^2 + 8xy - 4y^2)

Distribute, multiply each term in the parenthesis with the term outside of the parenthesis. Don't forget the laws of exponents, when one multiplies two exponents, with the same base, then one adds the two exponents. A number with no exponential term is two the first degree meaning that it is to the power of one.

-0.5x^3 y - 4x^2 y^2 + 2xy^3

4 0
3 years ago
Identify the data set that could be quadratic. HELP ASAP!!
Ne4ueva [31]

Answer:

Option B can be quadratic.

Step-by-step explanation:

Take a look at the data.

A quadratic equation is of the form ,

y = ax^{2} +bx + c,

where, a,b,c are constants.

<em>To find an unknown equation of 3 variables,</em>

<em>we need 3 points lying on the equation.</em>

here they have given, 5 points, meaning all should lie on the curve.

<em>For first option,</em> inserting first 3 points to find equation, we get equation as,

y = x^{2} -4x +11, but the rest points don't satisfy the curve.

So first option is not quadratic.

Similarly, it can be shown that option C and D are also not quadratic.

While, in option B, it is clear that for every y, x is y squared,

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6 0
3 years ago
Which equations represent the line that is perpendicular to the line 5x − 2y = −6 and passes through the point (5, −4)? Select t
Pepsi [2]

Answer:

Step-by-step explanation:

Two lines are perpendicular if the first line has a slope of m and the second line has a slope of \frac{1}{-m}.

With this information, we first need to figure out what the slope of the line is that we're given, and then we can determine what the slope of the line we're trying to find is:

5x - 2y = -6

-2y = -5x - 6

y = \frac{5}{2}x + 3

We now know that m = \frac{5}{2} for the first line, which means that the slope of the second line is m = \frac{-2}{5}. With this, we have the following equation for our new line:

y = \frac{-2}{5}x + C

where C is the Y-intercept that we now need to determine with the coordinates given in the problem statement, (5, -4):

y = \frac{-2}{5}x + C

(-4) = \frac{-2}{5}(5) + C

-4 = -2 + C

C = -2

Finally, we can create our line:

y = \frac{-2}{5}x - 2

5y = -2x - 10

2x + 5y = -10

8 0
4 years ago
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